无法在Appium的弹出窗口中找到元素

Question

In my app profile I want to select Religion, so when I am clicking on Religion one pop up is opening and I have to choose one element from there, Only "Index" and "text" values are different for each element, "Id" same for all element.

1. But while taking "xpath" using "text" and "index" values, not getting the element.

2. I am using scroll to method also but not getting the element.

Thanks in advance.

Answer 1

get all the index and its corresponding religions and click by index number

List<WebElement> ls = driver.findElementsById("android:id/numberpicker_input");             
System.out.println("no of religions" + ls.size());              
ls.get(0).click

Answer 2

You can click by using click method:

driver.findElementByName("your religion name").click();

and scroll by using this method:

public void keepScrollingUntilElementFound(String name) {
        for (int i = 0; i < 10; i++) {
            if (isElementPresent("name=" + name)) {
                break;
            } else {
                scrollDown();
                scrollDown();
            }
        }
    }



 public void scrollDown() {
        Dimension size = driver.manage().window().getSize();
        int x = size.width / 2;
        int starty = (int) (size.height * 0.60);
        int endy = (int) (size.height * 0.10);
        driver.swipe(x, starty, x, endy, 2000);
    }



 public boolean isElementPresent(String name) {
        try {
            driver.findElementByName(name);
            return true;
        } catch (Exception e) {
            return false;
        }
    }