MySQL用日期范围计数两个表

Question

I have two tables with each of table having their same ID from the first time of Member Join.

Once the member has been Approved, he/she will be Rejected also for a some reason and condition.

The Query Result needs to sort by date ranges then counting total approves and total rejects based on each date from chosen ID.

In this case, I've selected for join_id 325.

Table approves:

join_id         approved_date
325             2016-03-20
326             2016-03-20
326             2016-03-20
325             2016-03-21
326             2016-03-21
325             2016-03-21
325             2016-03-21
327             2016-03-21
325             2016-03-22
327             2016-03-22
325             2016-03-22

Table rejects:

join_id         rejected_date
325             2016-03-20
325             2016-03-20
326             2016-03-20
325             2016-03-21
327             2016-03-21
325             2016-03-22
327             2016-03-22
325             2016-03-22

This is I've tried:

SELECT
approved_date,
COUNT(join_id) AS join_id
FROM approves
WHERE join_id = 325
AND approved_date BETWEEN '2016-03-19' AND '2016-03-26' + INTERVAL 1 DAY
GROUP BY DATE_FORMAT(approved_date, '%Y-%m-%d');

SELECT
rejected_date,
COUNT(join_id) AS join_id
FROM rejects
WHERE join_id = 325
AND rejected_date BETWEEN '2016-03-19' AND '2016-03-26' + INTERVAL 1 DAY
GROUP BY DATE_FORMAT(rejected_date, '%Y-%m-%d');

Results for join_id 325 I expected:

date_time|approves|rejected
2016-03-19|0|0
2016-03-20|1|2
2016-03-21|3|1
2016-03-22|2|2
2016-03-23|0|0
2016-03-24|0|0
2016-03-25|0|0
2016-03-26|0|0

Answer 1

select events.join_id, events.date, sum(approve) as approves, sum(reject) as rejects
    from (
        select join_id, approved_date as date, 1 as approve, 0 as reject from approves 
        union
        select join_id, rejected_date as date, 0 as approve, 1 as reject from rejects
    ) as events
    group by events.join_id, events.date
where events.join_id = ? -- Here you can have more complex condition

May not be very optimal but simplest I think.

Answer 2

Try this too

select t1.join_id, t1.counting as approved, t2.counting as rejected from
(
select join_id, count(*) as counting from approves group by join_id
) as t1 inner join 
(
select join_id, count(*) as counting from rejects group by join_id
) as t2 on t1.join_id=t2.join_id

Answer 3

Here's one way:

SELECT d, 
       COALESCE(approved_count, 0) AS approved_count, 
       COALESCE(rejected_count, 0) AS rejected_count
FROM ( 
  SELECT DISTINCT approved_date AS d
  FROM approves

  UNION 

  SELECT DISTINCT rejected_date
  FROM rejects) AS t1
LEFT JOIN (
   SELECT approved_date, COUNT(*) AS approved_count
   FROM approves
   GROUP BY approved_date
) AS t2 ON t1.d = t2.approved_date
LEFT JOIN (
   SELECT rejected_date, COUNT(*) AS rejected_count
   FROM rejects
   GROUP BY rejected_date
) AS t3 ON t1.d = t3.rejected_date
ORDER BY d