Cometchat，按发送日期顺序排序

Question

Good day,

I'm looking to order my cometchat chats by last sent date (For example: 1 day ago, 3 days ago, 8 days ago, etc..) for a private messaging system i am working to integrate.

However every time i run the command:

(select distinct(f.member_id) id, f.display_name username from    
cometchat m1, members f where (f.member_id = m1.from and m1.to = '1') 
or (f.member_id = m1.to and m1.from = '1')) order by sent desc 

Which is taken from the official cometchat admin panel, i am correctly displayed the information in question (however it's unorganized. It organizes itself by last member id from the members table. instead of that from cometchat.) This is the example: http://i.imgur.com/ZfqAerr.png

Now, if i use the following command:

(select distinct(f.member_id) id,sent, f.display_name username from    
cometchat m1, members f where (f.member_id = m1.from and m1.to = '1') 
or (f.member_id = m1.to and m1.from = '1')) order by sent desc 

It does output the "sent" times from cometchat, but it also ungroups all the messages sent (so it's like page by page, instead of group messaging.) Proof: http://i.imgur.com/dtJegw0.png

So what steps must i take in order to make it so it displays both tables accurately in a grouped format by last sent time?

This is the Cometchat table structure: i.imgur.com/s2Nf8xd.png

This is the members table structure: i.imgur.com/mcq2Pyp.png

Answer 1

Here is SQL that we would suggest to address this issue:

select 
  distinct(f.member_id) id, 
  f.display_name username, 
  max(sent) senttime 
from cometchat m1, members f 
where (f.member_id = m1.from and m1.to = '1') 
   or (f.member_id = m1.to and m1.from = '1') 
group by f.member_id 
order by sent desc

The group_by keeps messages sent from or to a particular member together.