带有特定参数的函数的c ++指针向量

Question

if I have a function and I want to make a pointer to it with a specific parameter I can use auto but like this:

void bar(int n){std::cout << n;}
auto foo = std::bind(bar, 2);

but if I want to make a vector of these pointers it doesn't work

std::vector<auto> v;

Answer 1

You could write vector<decltype(foo)> v; although that probably doesn't do what you want (other bind expressions may give incompatible types).

As mentioned in comments, std::function is designed for this purpose:

std::vector< std::function<void()> > v;

v.emplace_back( foo );
v.emplace_back( std::bind(bar, 2) );
v.emplace_back( []{ std::cout << 2; } );