[英]preg_match is not working good in my condition
This is my code to get content between html tags. 这是我的代码,以获取html标记之间的内容。
$stringtext=file_get_contents($url);
$frm1=htmlspecialchars($_REQUEST['from1']);
$to1=htmlspecialchars($_REQUEST['to1']);
$dt= find_between($newstr,$frm1,$to1);
function find_between($string, $start, $end, $trim = true, $greedy = false) {
$pattern = '/'.preg_quote($start,'\"').'(.*';
if (!$greedy) $pattern .= '?';
$pattern .= ')'.preg_quote($end,'/').'/s';
preg_match($pattern, $string, $matches);
$string = $matches[0];
if ($trim) {
$string = substr($string, strlen($start));
$string = substr($string, 0,-strlen($end));
}
return $string;
}
It return null. 它返回null。
if I write pattern like this 如果我写这样的模式
$pattern = '/<td valign\="top">(.*?)<\/td>/s';
It works fine. 工作正常。
This is html form to enter value of frm1 and to1. 这是HTML格式,用于输入frm1和to1的值。
<form action="" method="post" id="frm1" style="display:none">
<table>
<tr>
<td>From: <input type="text" name="from1" /></td>
<td>To: <input type="text" name="to1" /></td>
</tr>
</table></form>
As Casimimir has already pointed out, use a Parser (eg SimpleXML
) instead. 正如Casimimir已经指出的那样,请改用解析器(例如SimpleXML
)。
Consider the following code with two alternatives: 考虑以下代码,并提供两种选择:
<?php
$html = '
<form action="" method="post" id="frm1" style="display:none">
<table>
<tr>
<td>From: <input type="text" name="from1" /></td>
<td>To: <input type="text" name="to1" /></td>
</tr>
</table></form>
';
$xml = simplexml_load_string($html);
# traverse the DOM directly
$input_version1 = $xml->table->tr->td->input;
# use an xpath query to get the same element
$input_version2 = $xml->xpath("//form//input[@name='from1']")[0];
print_r($input_version1);
print_r($input_version2);
?>
A good introduction to SimpleXML
can be found here . 在这里可以找到对SimpleXML
的很好介绍。
function find_between($string, $start, $end, $trim = true, $greedy = false) {
$start=htmlspecialchars_decode($start);
$end=htmlspecialchars_decode($end);
$pattern = '/'.preg_quote($start,'\"').'(.*';
if (!$greedy) $pattern .= '?';
$pattern .= ')'.preg_quote($end,'/').'/s';
preg_match($pattern, $string, $matches);
$string = $matches[0];
if ($trim) {
$string = substr($string, strlen($start));
$string = substr($string, 0,-strlen($end));
}
return $string;
}
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