[英]c# Regex problem
i want search a value in on row like this 我想像这样在行中搜索值
<p align="center"><input type="hidden" name="e79e7ec" value="15302f565b">
i need name="" value and value="" value :P create this code , but this code dosent work 我需要name =“” value和value =“” value:P创建此代码,但此代码有效
Regex rloginRand = new Regex(@"<p align=center><input type=hidden name=\w*");
Match mloginRand = rloginRand.Match(source);
string loginrand = "";
if (mloginRand.Success)
{
loginrand = mloginRand.ToString().Replace("<p align=center><input type=hidden name=", "");
}
string loginrnd = "";
Regex rloginRnd = new Regex(@"name="+ loginrand+"value=\w*");
Match mloginRnd = rloginRnd.Match(source);
if (mloginRand.Success)
{
loginrnd = mloginRnd.ToString().Replace("name="+loginrand+" value=", "");
}
error is 错误是
Form1.cs(71,69): error CS1009: Unrecognized escape sequence Form1.cs(71,69):错误CS1009:无法识别的转义序列
at this line 在这条线
Regex rloginRnd = new Regex(@"name="+ loginrand+"***value=\\w****"); 正则表达式rloginRnd =新正则表达式(@“ name =” + loginrand +“ *** value = \\ w ****”);
Regex is not always the best tool for HTML; 正则表达式并不总是HTML的最佳工具。 I'd use the HTML Agility Pack (since it isn't xhtml), and xpath - it should be pretty trivial then: 我将使用HTML Agility Pack (因为它不是xhtml)和xpath-那么它应该是很简单的:
HtmlDocument doc = new HtmlDocument();
doc.LoadHtml(html);
HtmlNode node = doc.DocumentNode.SelectSingleNode("input");
// read (if you want)
string name = node.GetAttributeValue("name", ""),
value = node.GetAttributeValue("value", "");
// wipe
node.SetAttributeValue("name", loginrand);
node.SetAttributeValue("value", "");
// get html
html = doc.DocumentNode.OuterHtml;
use 采用
Regex rloginRnd = new Regex(@"name="+ loginrand+@"*value=\\w**");
Note: Second @ sign 注意:第二个@符号
or 要么
Regex rloginRnd = new Regex(@"name="+ loginrand+"*value=\\\\w**");
Note: Double \\ before w 注意:w前加双\\
您需要在字符串的每个部分之前添加一个@
:
Regex rloginRnd = new Regex(@"name="+ loginrand+@"value=\w*");
I don't think the @ covers the entire string concatination, only the bit that it's on. 我不认为@覆盖整个字符串的混叠,只覆盖了它的一部分。
Try. 尝试。
Regex rloginRnd = new Regex(@"name="+ loginrand+ @"*value=\w**");
or 要么
Regex rloginRnd = new Regex(@"name="+ loginrand+ "*value=\\w**");
or use string.format 或使用string.format
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