lodash：深层复制对象，但不是所有属性

Question

Is there any way to copy an object with lodash, but not all properties. The only way I know is manually copying it property by property

wanted eg:

var obj = {
    a: 'name',
    b: [1,2,3],
    c: {
        z: 'surname',
        x: []
    },
    d: {
        y: 'surname2',
        w: []
    }
};

and the result be like

var copy_obj = {
    b: [1,2,3],
    c: {
        z: 'surname',
        x: []
    }
};

Edit: I finally opted for:

var blacklist = ['a','d'];
_.cloneDeep(_.omit(obj, blacklist));

Answer 1

The omit serves almost this exact purpose:

_.cloneDeep(_.omit(obj, blacklist));

Fiddle here: https://jsfiddle.net/c639m9L2/

Answer 2

你可以使用选择功能：

_.pick(obj, 'b', 'c')

Answer 3

您可以使用第二个参数JSON.stringify来执行此操作。

JSON.parse(JSON.stringify(obj, ['b', 'c']))

Answer 4

You can use a combination of assign and pick

Object.assign(copy_obj, _.pick(obj, ['b', 'c']));

In this way if copy_obj has other properties you don't override them.

Answer 5

var blacklist = ['a','d'];
_.cloneDeep(_.omit(obj, blacklist));