查找日期是否少于现在的7天

Question

How can i find out if expiry date is less than 7 days from now?

The expiry date format looks like this: 2016-04-13

I have a code here, but it doesn't work:

if($record->$c < date('Y-m-d', strtotime('-7 day'))){
   // this is true
}

Hope anyone could help me.

Answer 1

Just convert both units to unix timestamp, make your subtraction, then divide it by 86400:

$expiry_date = '2016-04-18';
$today = time();
$interval = strtotime($expiry_date) - $today;
$days = floor($interval / 86400); // 1 day
if($days < 7) {
    echo 'less';
}

Or another way with DateTime classes:

$expiry_date = '2016-04-18';
$expiry_date = new DateTime($expiry_date);
$today = new DateTime();
$interval = $today->diff($expiry_date);
$day = $interval->format('%r%a');
if($day < 7) {
    echo 'less';
}

Example conditions:

$expiry_date = '2016-04-18';
$today = time();
$interval = strtotime($expiry_date) - $today;
$day = floor($interval / 86400); // 1 day
if($day >= 1 && $day < 7) {
    echo 'between 1 - 7 days';
} elseif($day <= 0) {
    echo 'deadline';
} else {
    echo 'soon';
}

Just change / tweak it depending on what you're trying to do.

Answer 2

Recommend exploring date_diff() function:

http://php.net/manual/en/function.date-diff.php

My challenge was different:

// Count days is date range 
function count_days_in_range($date1, $date2) {

    $date1      = date_create($date1);
    $date2      = date_create($date2);

    $interval   = date_diff($date1, $date2);
    $days       = $interval->days;

    return $days;
}

But this function will make your life much easier.