使用筛选方法从数组中删除值

Question

Given an array and subsequent unknown number of arguments, how can I remove all elements from the initial array that are of the same value as these arguments? This is what I have so far:

function destroyer(arr) {
    var arrayOfArgs = [];
    var newArray = [];
    for (var i = 0; i < arguments.length; i++) {
        newArray = arr.filter(function (value) {
            return value !== arguments[i + 1];
        });
    }
    return newArray;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Answer 1

You can use Array#filter with arrow function Array#includes and rest parameters .

Demo

function destroyer(arr, ...remove) {
    return arr.filter(e => !remove.includes(e));
}

console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));

 function destroyer(arr, ...remove) { return arr.filter(e => !remove.includes(e)); } var updatedArr = destroyer([1, 2, 3, 1, 2, 3], 2, 3); console.log(updatedArr); 

Equivalent Code in ES5:

function destroyer(arr) {
    var toRemove = [].slice.call(arguments, 1);
    return arr.filter(function(e) {
        return toRemove.indexOf(e) === -1;
    });
}

console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));

 function destroyer(arr) { var toRemove = [].slice.call(arguments, 1); return arr.filter(function (e) { return toRemove.indexOf(e) === -1; }); } console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3)); 

Answer 2

Use rest parameters to specify the subsequent arguments, Array.prototype.filter() with an arrow function to filter the arr , and Array.prototype.includes() to determine whether args contains specific item.

function destroyer(arr, ...args) {
  return arr.filter(x=> !args.includes(x))
}

console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3))