[英]How to regex last part of URL only?
I want to do a regex that target the end of a url: 我想做一个针对网址结尾的正则表达式:
www.company.com/orders/
thanks www.company.com/orders/
谢谢
If you return from email or account page order ID is populated in the end: 如果您是从电子邮件中返回或帐户页面,那么最后将填充订单ID:
www.company.com/orders/thanks/ 1sfasd523425 www.company.com/orders/thanks/ 1sfasd523425
So I only want to target the URL that ends with /thanks 所以我只想定位以/ thanks结尾的URL
This thread bring is similiar: How do I get the last segment of URL using regular expressions 该线程带来的相似之处: 如何使用正则表达式获取URL的最后一段
Had something similair .*\\/thanks\\/.+
but target incorrectly. 有点类似
.*\\/thanks\\/.+
但定位不正确。
EDIT: Only target URLs ending with /thanks or /thanks/ 编辑:仅以/ thanks或/ thanks /结尾的目标URL
Try with lookahead like this. 像这样先行尝试。
Regex: .+(?=\\/thanks$).+
正则表达式:
.+(?=\\/thanks$).+
Explanation: This will match the URL only if thanks
is at end of string by positive lookahead
. 说明:仅当在
positive lookahead
的字符串末尾thanks
时,才与URL匹配。
Use URL object dont parse it yourself
URL url = new URL("http://stackoverflow.com/questions/36616915/how-to-regex-last-part-of-url-only");
URLDecoder.decode(url.getPath(), "utf-8");
url.getPath();
url.getContent();
url.getPort();
url.getContent();
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