如何测试仅包含字母字符和破折号（-）的字符串[javascript]

Question

I need to create a regex for a word that contains only letter characters and the dash symbol (-). It can not be repeated in succession (eg --). Here's my regex function:

var regex = new RegExp(/(\w*\-{0,1})*/);

This function should work for a word like: home-do g or even something like, home-dog-bird but not for something like home--dog . How can I test this?

Answer 1

You can do that using negative look ahead.

var regex=new RegExp(/^(\w|-(?!-))+$/);

What this does is matching something that contains only alphanumeric characters and - only if it's not followed by another - .

See https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions for more details on what's possible with the javascript regular expressions.

Answer 2

If you think about it the other way around (going backwards rather than forwards), you could make a regex that asserts that each match begins with one or more word characters and is followed by zero or more single dash, word pairs

https://regex101.com/r/xT7aT5/2

/^\w+(-\w+)*$/

Not sure if this is the best approach though. I like Py.'s answer best atm.

Answer 3

另一个没有提前通知的人：

/^(-?\w+)*-?$/

Answer 4

Another solution which looks for word and optional for a single dash and words.

 function match(s) { return !!s.match(/^\\w+(\\-\\w+)*$/g); } document.write(match('dog') + '<br>'); document.write(match('dog-cat') + '<br>'); document.write(match('dog-cat-fish') + '<br>'); document.write(match('dog-cat--fish') + '<br>'); 

Answer 5

您也可以尝试以下方法：

var regex = new RegExp(/^(\w*(\-\w)\w*)*$/);

Answer 6

This will match in a body of text.

/\w+(-\w+)+/

https://regex101.com/r/hU0xH7/1

Answer 7

试试这个正则表达式/^([^-]*-{0,1}[^-]*)$/