[英]Printing an Arraylist in toString with lines separating each entry
I have a toString that needs to print a lot of stuff, including an Arraylist which contains multiple entries. 我有一个toString,需要打印很多东西,包括一个包含多个条目的Arraylist。 Those entries have to be separated by a new line.
这些条目必须用新行分隔。 Here is the toString code that I am working with right now:
这是我现在正在使用的toString代码:
@Override
public String toString() // Displays the info for a class
{
return getCourseId() + "\n" + getCourseName() + "\n" + getCourseCode()
+ "\n" + "\n" + "Instructor" + "\n" + "-------------------------"
+ "\n" + Instructor.toString() + "\n" + "\n" + "Student Roster"
+ "\n" + "-------------------------" + "\n" + roster;
}
The roster does print, but all of the entries exist on the same line with brackets and commas. 名册确实会打印,但是所有条目都在同一行中,并带有方括号和逗号。
My instructor insists that the toString be self-contained, so everything that I have in the toString currently has to stay there. 我的老师坚持说toString必须是独立的,所以我在toString中拥有的所有内容目前都必须呆在那里。
The roster prints like this: 名册打印如下:
@Override
public String toString() // Displays the info for a person in order
{
return getPersonId() + "\t" + getLastName() + "\t" + getFirstName()
+ "\t" + getMajor() + "\t" + getGpa();
}
Currently, I get the output that looks like this: 当前,我得到的输出看起来像这样:
10000
College Algebra
MATH 101
Instructor
-------------------------
X00009876 Jones Jane Associate Professor Mathematics
Student Roster
-------------------------
[X00000002 Smith Sally History 2.98, X00000003 Adams Amanda Civil Engineering 3.7, X00000005 Turner Thomas Nursing 2.34]
But I would like it to look like this: 但我希望它看起来像这样:
10000
College Algebra
MATH 101
Instructor
-------------------------
X00009876 Jones Jane Associate Professor Mathematics
Student Roster
-------------------------
X00000002 Smith Sally History 2.98
X00000003 Adams Amanda Civil Engineering 3.7
X00000005 Turner Thomas Nursing 2.34
Any suggestions would be greatly appreciated. 任何建议将不胜感激。 Thanks!
谢谢!
Try this: 尝试这个:
String rosterStr = roster.stream()
.map(r -> r.toString())
.collect(Collectors.joining("\n"))
Which will get the string for each value in roster, and then join them with newlines 它将获取花名册中每个值的字符串,然后将它们与换行符连接
I'm not sure exactly what you're asking, but I would suggest using the StringBuilder class, as follows: 我不确定您要问的是什么,但是我建议使用StringBuilder类,如下所示:
@Override
public String toString() {
StringBuilder sb = new StringBuilder();
//You haven't provided much info about your ArrayList, customise this accordingly
for (Object o : ArrayList<Object>) {
sb.append(o.toString() + " ");
}
sb.setLength(sb.length() - 1);
return getCourseId() + "\n" + getCourseName() + "\n" + getCourseCode()
+ "\n" + "\n" + "Instructor" + "\n" + "-------------------------"
+ "\n" + Instructor.toString() + "\n" + "\n" + "Student Roster"
+ "\n" + "-------------------------" + "\n" + sb.toString();
}
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