将使用烧瓶获得的变量作为脚本的输入传递

Question

I have a python setup where one method continuously returns the IDs of scanned RFID chips. Now I cut the cord and have the scanner hooked up to a wifi microcontroller (ESP8266). Every time a chip is scanned a GET request is issued containing the chip's ID.

I put the flask part in a simple script. I don't need anything returned to the ESP8266. I would like to just have a class or functions that just return the collected value. I can print the value to stdout where it appears also with flask's log output but this doesn't really help. How do I pass uid to a different script, what am I missing?

The script in question:

from flask import Flask

app = Flask(__name__)

@app.route('/urlpath/<uid>')
def rfiduid(uid):
    print uid

if __name__ == '__main__':
    app.run(host='0.0.0.0', debug=False)

Answer 1

You would just need to import your other and call it directly from within the route.

from flask import Flask

# A module which contains the stuff you're trying to do
from myothermodule import processRFID

app = Flask(__name__)

@app.route('/urlpath/<uid>')
def rfiduid(uid):
    # Pass the UID to your other module here
    processRFID(uid)

if __name__ == '__main__':
    app.run(host='0.0.0.0', debug=False)

If your other code is literally a script (that accepts input arguments from the command line) I would recommend modifying it so that it contains a function that you can call from the flask app. Otherwise, you will need to use an os.system call or something to execute the other script with arguments. This is highly discouraged since you are passing un-sanitized user input (via the url) to your system.

@app.route('/urlpath/<uid>')
def rfiduid(uid):
    os.system(' '.join(['script.py', uid]))

This could be exploited if a UID were passed as '1 && really_bad_system_command'