php类函数作为$ this->的参数

Question

I have a webservice class with a number of private functions. I have a main function which decides which function to call according to the first parameter of the web service call.

$actions = [
        "CHECK_LOGIN"     => "checkLogin" 
    ,   "CHECK_FB"        => "checkFB"  
    ,   "GET_DETAILS"     => "getDetails" 
    ,   "SAVE_DETAILS"    => "saveDetails" 
    ,   "CHANGE_PWD"      => "saveDetails" 
    ,   "SEND_ECODE"      => "sendEmailCode"
]

So, its easy to find which function to call according to the parameter passed:

if (!array_key_exists($action, $actions))
  $rep = ["status" => STATUS_ERROR, "errMsg" => "Action '$action' unknown"];
else {
   $method = $actions[$action];
   $rep = $method($req);
}

My problem is that I can't call "$method" what ever it is (eg "checkFB"), I need to call $this->method (ie "$this->checkFB") How do I put the $this-> in front of the function name found in the $actions array??

Answer 1

You can do it like this:

if (!array_key_exists($action, $actions))
  $rep = ["status" => STATUS_ERROR, "errMsg" => "Action '$action' unknown"];
else {
   $method = $actions[$action];
   $rep = $this->$method($req);
}