使用两个列表将字典转换为带有 Python 中值列表的字典

Question

I have two list like

['a','b','c']
['x','y','z']

I want to create a dictionary which holds values as list like,

{'a':['x'],'b':['y'],'c':['z']}

I am using like this but gives me values not in list :

dictionary = dict(zip(out_head, (select11)))

Please suggest.

Answer 1

This creates a list for each element in select11

dictionary = dict(zip(out_head,
                        ([x] for x in select11)
                        ))

Alternatively (@kpie reminds me of dict-comprehension notation):

dictionary = {k:[v] for k,v in zip(out_head, select11)}

Answer 2

Try calling list on each element in the second list before zipping them.

x, y = ['a','b','c'], ['x','y','z'] 
new = dict(zip(x, [list(i) for i in y]))
print new

Answer 3

I think the syntax you are looking for is this.

a = [1,2,3]
b = ['a','b','c']
d = {k:[v] for (k,v) in [(q,w) for q in a for w in b]}

Answer 4

a = ['a','b','c'] b = ['x','y','z']

dict(zip(a,map(list, b)))

The map(list) wraps each member of list b in its own list, which is what you say you want.

Answer 5

Use this.

 keys = ['a', 'b', 'c']
 values = ['x', 'y', 'z']
 dictionary = dict(zip(keys, list(values)))