是什么使这个输出HTML的php代码起作用？

Question

I'm trying to output a button using PHP but I cant seem to get the ' and " correctly.

This is the output I should be getting from the PHP code below:

<button class="button button1" onclick="buttonTest(99.16918,-82.9191)"> Lithuania </button>    

This is my code:

foreach ($getClasses as $row){
echo '<button class="button button1" onclick="buttonTest(', $row->BUILDING_Latitude ,',',$row->BUILDING_Longtitude,)>', $row->COURSE_Title,'</button>';
}

how do i get php to output this html code above i get an error

syntax error, unexpected '>' (48) : eval()'d code

syntax error, unexpected ')', expecting ',' or ';' (48) : eval()'d code

Update

Also, please advice me the best way to rewrite this, so that these kind of issues do not occur in the future.

Answer 1

You missed the ' here:

tude, ')">', $ro
//----^-^

Full code:

echo '<button class="button button1" onclick="buttonTest(', $row->BUILDING_Latitude ,',',$row->BUILDING_Longtitude, ')">', $row->COURSE_Title,'</button>';
//------------------------------------------------------------------------------------------------------------------^-^

I would really write this way:

<?php
    foreach ($getClasses as $row) {
        echo "<button class=\"button button1\" onclick=\"buttonTest({$row->BUILDING_Latitude}, {$row->BUILDING_Longtitude})\">{$row->COURSE_Title}</button>";
    }

Or even better:

<?php
    foreach ($getClasses as $row) {
        $lat = $row->BUILDING_Latitude;
        $lon = $row->BUILDING_Longtitude;
        $course = $row->COURSE_Title;
        echo "<button class=\"button button1\" onclick=\"buttonTest($lat, $lon)\">$course</button>";
    }