使用弹簧数据获取键值的mongodb查询

Question

I've been started a project with mongodb and spring boot and spring JPA data and I realised I cannot map my data model to entity and make a query on that easily, so I have two questions,

My data model is like that ( just for one Collection )

{
   name: "Name",
   lastName: "Last Name",
   attributes: {
      age: 25
      eye: {
         color: "RED",
         size: "BIG"
      }
   }
}

And my entity is

@Entity // or @Document
public class User{
   private String name;
   private String lastName;
   private Map<String, ?> attributes = new HashMap<>();

   // id or the setter getter are omitted
}

1. Can I map attributes property in my mongodb collection like I did ( Map )

2. How can I make query for finding the attributes?

   Can I do it like that? List<User> findAllByAttributesAge(Integer age);

Answer 1

Can I map attributes property in my mongodb collection like I did ( Map )

Yes, you can, and it may prove useful (though tricky) for a " dynamic " or " partly defined " schema.

If you know your schema in advance, I strongly recommend that it shows in your domain object. Take a look here .

How can I make query for finding the attributes?

If you don't use a dynamic schema, property traversal for nested properties is clearly explained in the Spring Data MongoDB Reference Documentation .

If you use dynamic schema, you'll most probably use MongoDB JSON based query methods .

Answer 2

Today I had a problem with Map query in Spring Mongodb, and since this question pops the first one in google I will provide another answer.

Since the other answer references to documentation, and that documentation does not have a lot of information, I am going to put an example of how good is the @Query annotation for dynamic schema:

@Query(value = "{'attributes.age' : ?0}")
List<User> findAllByAttributesAge(int age);

Also, you could query eye color, too:

@Query(value = "{'attributes.eye.color' : ?0}")
List<User> findAllByAttributesEyeColor(String color);

As the other answers documentation says, you could filter the result, and receive only the part of the document that you prefer:

// It will return the users with only name and last name
@Query(value = "{'attributes.age' : ?0}", fields = "{ name : 1, lastName : 1 }")
List<User> findAllByAttributesAge(int age);