Python：1个函数能否接受来自2个不同功能的变量

Question

OK - I am trying to get a Python function to accept variables from two other functions. Is this possible ?

A sample of what I am trying to do it below (I have simmed down the original code - for input here). Hopefully you get theidea of what I am trying to do. In a nutshell, I have Rectangle () which calls Extras() and the I want the output from Rectangle and Extras to be sent to the Calculate_Deposit ().

Is this possible ?

def calculate_deposit(total_cost, extras):
    deposit_percent = float(raw_input("Enter Deposit % (as a decimal) of Total Cost:    "))
    months_duration = float(raw_input("Enter the number of months client requires:    "))
    if deposit_percent >0:
        IN HERE JUST SOME CALCULATIONS
    else:
        print "The total amount required is:     ", total_cost

def rectangle(width, height, depth, thickness):
    type = raw_input("Enter lowercase c for concrete:  ")
    if type == 'c':
        output = IN HERE JUST COME CALCULATIONS
    else:
        return raw_input("Oops!, something went wrong")     
    print output + extras()
    total_cost = calculate_deposit(output, extras)                          

def extras():
    type = float(raw_input("Enter 1 for lights:  "))
    if type == 1:
        light = 200
        print "The cost of lights are:    ", light
        return light
    else:
        return raw_input("No extras entered")

Answer 1

In rectangle , you call extras() , then you send just the function extras to calculate_deposit() . You want to send the result of the extras() call, not a reference to the function itself. You can make a minor change and save that value, referring to it when you print and when you go into calculate_deposit .

Change this:

print output + extras()
total_cost = calculate_deposit(output, extras)

To this:

extra = extras()
print output + extra
total_cost = calculate_deposit(output, extra)