Swift中有一个变量的两个函数

Question

I have two functions in a view controller. The first function parses JSON and makes an array; another generates a table with the array data. The problem is that it seems that the first function cannot send its array data to the second function.

Here is the code:-

class secondViewController: UIViewController, UITableViewDataSource {
    let chartTitle:[String] = ["Name",......]

    func parseJSON(){
        let url = NSURL(string: "http://00000.us-west-2.elasticbeanstalk.com/index.php?000000")
        let request = NSURLRequest(URL: url!)
        do {
            let data = try NSURLConnection.sendSynchronousRequest(request, returningResponse: nil)
            do {
                let json = try NSJSONSerialization.JSONObjectWithData(data, options: .MutableContainers)
                var name = json["Name"]
                var chartContent:[String] = ["\(name)",.....]   //Contents of current chart contents
            } catch{
                //Handle Exception
            }
        } catch{
            //Handle Exception
        }
    }

    override func viewDidLoad() {
        parseJSON()
        ...
    }


    func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {   //currnet table information.
        let cell = UITableViewCell()
        cell.textLabel?.text = chartTitle[indexPath.row] + "\t\t\t\t\t here comes info" + chartContent[indexPath.row]
    }

    func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return chartTitle.count
    }
}

This code has an error at the tableView function:

Use of unresolved identifier 'chartContent'

I tried to declare the variables outside the first function which is right under the class secondViewController but there was another error on UITableViewDataSource .

Any solution for these?

Answer 1

Charttitle is defined outside any procedure, so it's available everywhere. Chartcontent is defined in a block, so it's usable just in it's block

Answer 2

Its because chartContent is a local variable just available to parseJson func only and its scope is till that func block. You have to create this variable the same way you dis chartTitle to be available throughout the class.