如何将文本文件中的数字作为数字读取到列表中？

Question

I have a text file in which there are numbers in each line(only numbers). My color.txt looks like:

3
3
5
1
5
1
5

When I read this to list using

f=open('D:\\Emmanu\\project-data\\color.txt',"r")
    for line in f:
        g_colour_list.append(line.strip('\n'))
    print g_colour_list

the output is like

['3', '3', '5', '1', '5', '1', '5']

But I want it as:

[3,3,5,1,5,1,5]

How can I do that in the single line that is
g_colour_list.append(line.strip('\\n')) ?

Answer 1

只需将您的字符串转换为整数：

g_colour_list.append(int(line.strip('\n')))

Answer 2

Wrap a call to python's int function which converts a digit string to a number around your line.strip() call:

f=open('D:\\Emmanu\\project-data\\color.txt',"r")
    for line in f:
        g_colour_list.append(int(line.strip('\n')))
    print g_colour_list

Answer 3

One possible solution is to cast the string to integer on appending. You can do it this way :

g_colour_list.append(int(line.strip('\n')))

If you think you will get floats as well then you should use float() instead of int() .

Answer 4

for line in f:
    g_colour_list.append(int(line.strip('\n')))

You can parse a string s to int with int(s)

Answer 5

You can typecast it to int, doing:

f = open('color.txt',"r")
g_colour_list=[]

for line in f:
    g_colour_list.append(int(line.strip('\n')))

print (g_colour_list)