[英]persist/update collection of data into database using hibernate
I am newbie to Hibernate framework and I am curious about the way persist and update work. 我是Hibernate框架的新手,我很好奇持久化和更新工作的方式。
Currently in my project when I would like to persist or update collection of data into database, I am doing it one by one via looping method. 目前在我的项目中,当我想将数据集合持久化或更新到数据库中时,我是通过循环方法逐个完成的。 For instance,
例如,
public persistData(){
List<Person> personList = new ArrayList<>();
for(Person person : personList){
session.persist(person);
}
}
Is it possible to, for example, 例如,是否有可能
session.persist(personList);
Or there is anyway else I can persist/update collection of data at once without looping? 或者还有其他方面我可以一次性持久/更新数据集合而不循环?
Editted: I have found Hibernate Batch Processing in How to insert multiple rows into database using hibernate? Editted:我在如何使用hibernate将多行插入数据库中找到了Hibernate Batch Processing ? and Best way to insert a good amount of records in hibernate
和在hibernate中插入大量记录的最佳方法
I am developing generic class for persist/update/delete data with hibernate, should I provide the method with 我正在使用hibernate开发持久化/更新/删除数据的泛型类,我应该提供方法
public void (List<T> addedItemList)
or 要么
public void (T addedItem)
For my understanding, bulk persist should be done with large amount of transactions right? 根据我的理解,批量持续应该用大量的交易完成吗? If some times there is only 1 or 2 objects to be persisted, is batch processing still appropriate?
如果有时只有1或2个对象要保留,批处理是否仍然合适?
The main point here is to begin the transaction, persist all, and then commit. 这里的要点是开始事务,持久化所有,然后提交。 Try not using the @Transaction since you are doing it with the code.
尝试不使用@Transaction,因为您正在使用代码。
EntityManager em = entityManagerProvider.get();
// em.clear();//remove this if caching is necessary
em.getTransaction().begin();
for(buildings b:buildingsArray) {
em.persist(b);
}
em.getTransaction().commit();
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