值不能为null或为空。\ r \ nParameter name：name

Question

when i go to cshtml page this error occur:

An exception of type 'System.ArgumentException' occurred in System.Web.Mvc.dll but was not handled in user code

in my cshtml code :

<div class="form-group">
     @Html.Label("Model", new { @class = "control-label col-md-4" })
  <div class="col-md-8">
     @Html.Editor("Model")
  </div>
</div>

but on the other hand if i change my code in @Html.Editor("PropertyModel")

it is working perfectly no error occur .

UPDATE:

in my model:

public class PropertyAssign {
        public int PropertyAssignId { get; set; }

        public string PropertyName { get; set; }

        public string Model { get; set; }


        public DateTime AssignDate { get; set; }
    }

In My Controller:

 public ActionResult Create()
    {
      return View();
    }

Answer 1

I've tryed this case and it's very strange, but there is some problem with the identifier of your Model property with usage of @Html.Editor() helper.

@Html.Editor("Model") // throws an exception
@Html.EditorFor(m => m.Model) // works fine

Maybe in this context the meaning of Model is the whole model, which is passed to the view, not the single property. But when I've changed the identifier of the Model property to some other, for example SomeModel, everything is fine.

@Html.Editor("SomeModel") // works fine
@Html.EditorFor(m => m.SomeModel) // works fine

So, the possible solutions are:

• to change the Editor helper you use or
• to change your property identifier

Answer 2

The reason the exception is thrown is that the HtmlHelpers inspect ViewData to get the values to bind to. ViewData is typeof ViewDataDictionary which contains a property Model (which is the model you pass to the view).

In your case, you do not return a model to the view so ViewData.Model is null and the exception is thrown.

To solve this, use the strongly typed EditorFor(m => m.Model) (or TextBoxFor(m => m.Model) which you should be doing in any case. Even if you do not pass a model to the view, this will still generate the correct html without throwing an exception.

<input type="text" name="Model" id="Model" value="" />

but its best practice to pass a model anyway, so your controller method should be

public ActionResult Create()
{
  return View(new PropertyAssign());
}

Answer 3

write using your model name at the top like

@using projectNamespace.PropertyAssign 

when using editor for your some property you can write like

@Html.EditorFor(m => m.PropertyName) 

for text box its

@Html.TextBoxFor(model => Model.PropertyAssign , new { @class = "release-prefix" @id = "prefix" })