输入字段值 - 删除前导零

Question

I have a textbox in Javascript. When I enter '0000.00' in the textbox, I want to know how to convert that to only having one leading zero, such as '0.00' .

Answer 1

More simplified solution is as below. Check this out!

var resultString = document.getElementById("theTextBoxInQuestion")
                           .value
                           .replace(/^[0]+/g,"");

Answer 2

str.replace(/^0+(?!\.|$)/, '')

  '0000.00' --> '0.00'   
     '0.00' --> '0.00'   
  '00123.0' --> '123.0'   
        '0' --> '0'  

Answer 3

var value= document.getElementById("theTextBoxInQuestion").value;
var number= parseFloat(value).toFixed(2);

Answer 4

It sounds like you just want to remove leading zeros unless there's only one left ("0" for an integer or "0.xxx" for a float, where x can be anything).

This should be good for a first cut:

while (s.charAt(0) == '0') {            # Assume we remove all leading zeros
    if (s.length == 1) { break };       # But not final one.
    if (s.charAt(1) == '.') { break };  # Nor one followed by '.'
    s = s.substr(1, s.length-1)
}

Answer 5

Ok a simple solution. The only problem is when the string is "0000.00" result in plain 0. But beside that I think is a cool solution.

var i = "0000.12";
var integer = i*1; //here's is the trick...
console.log(i); //0000.12
console.log(integer);//0.12

For some cases I think this can work...

Answer 6

You can use this code:

<script language="JavaScript" type="text/javascript">
<!--
function trimNumber(s) {
  while (s.substr(0,1) == '0' && s.length>1) { s = s.substr(1,9999); }
  return s;
}

var s1 = '00123';
var s2 = '000assa';
var s3 = 'assa34300';
var s4 = 'ssa';
var s5 = '121212000';

alert(s1 + '=' + trimNumber(s1));
alert(s2 + '=' + trimNumber(s2));
alert(s3 + '=' + trimNumber(s3));
alert(s4 + '=' + trimNumber(s4));
alert(s5 + '=' + trimNumber(s5));
// end hiding contents -->
</script>

Answer 7

试试这个：

<input type="text" onblur="this.value=this.value.replace(/^0+(?=\d\.)/, '')">

Answer 8

You can use a regex to replace the leading zeroes with a single one:

valueString.replace(/^(-)?0+(0\.|\d)/, '$1$2')

>'-000.0050'.replace(/^(-)?0+(0\.|\d)/, '$1$2')
< "-0.0050"
>'-0010050'.replace(/^(-)?0+(0\.|\d)/, '$1$2')
< "-10050"

Matches: <beginning of text><optional minus sign><any sequence of zeroes><either a zero before the dot or another digit>

Replaces with: <same sign if available><the part of the string after the sequence of zeroes>

• ^ is the beginning of text

• ? means optional (refers to the previous character)

• (a|b) means either a or b

• . is the dot (escaped as . has a special meaning)

• \\d is any digit

• $1 means what you found in the first set of ()

• $2 means what you found in the second set of ()