[英]MYSQL - Select MIN and MAX year and fill the gaps
I want to use Highcharts (bar) with my database, but I am struggling how to bring the JSON using my select.我想在我的数据库中使用 Highcharts (bar),但我正在努力如何使用我的选择带来 JSON。
I have three levels: Gold, Silver, Platinum and I need to get the minimum year and maximum year and cover the gaps if that level is not present in some year我有三个级别:黄金、白银、白金,我需要获得最小年份和最大年份,如果某个年份没有该级别,我需要弥补差距
I have this select:我有这个选择:
select B.year, A.level, COUNT(B.id_level) as n_level from level AS A
inner join company_level AS B ON A.id_level = B.id_level
GROUP BY B.id_level, B.year
ORDER BY B.year
My result:我的结果:
year level n_level
2010 Siver 1
2010 Platinum 2
2010 Gold 2
2011 Gold 1
2013 Gold 1
2014 Platinum 1
2015 Silver 1
In my result I don't have Silver and Platinum for 2011 and I would like to put the Silver and Platinum in the list but with number_level (n_level) with 0.在我的结果中,我没有 2011 年的 Silver 和 Platinum,我想将 Silver 和 Platinum 放在列表中,但 number_level (n_level) 为 0。
My PHP:我的PHP:
$rows = mysqli_query($this->conn, $query);
$bln = array();
$bln['name'] = 'Year';
$row['name'] = 'Level';
$year ="";
while ($r = mysqli_fetch_array($rows)) {
if($year !== $r['year']){
$bln['data'][] = $r['year'];
}
$row['data'][] = $r['n_level'];
$year = $r['year'];
}
$rslt = array();
array_push($rslt, $bln);
array_push($rslt, $row);
print json_encode($rslt, JSON_NUMERIC_CHECK);
My PHP Result:我的 PHP 结果:
[{"name":"Year","data":[2010,2011,2013,2014,2015]},{"name":"Level","data":[2,2,1,1,1,1,1]}]
But my goal is:但我的目标是:
[{"name":"Year","data":[2010,2011,2013,2014,2015]},{"name":"Gold","data":[2,2,1,1,1]}, {"name":"Silver","data":[1,0,0,0,1]}, {"name":"Platinum","data":[2,2,1,1,1]}]
Thank you for any help.感谢您的任何帮助。
Result after @Tin Tran answer: @Tin Tran 回答后的结果:
$rows = mysqli_query($this->conn, $query);
$bln = array();
$bln['name'] = 'Year';
$row_gold['name'] = 'Gold';
$row_platinum['name'] = 'Platinum';
$row_silver['name'] = 'Silver';
while ($r = mysqli_fetch_array($rows)) {
$bln['data'][] = $r['year'];
$row_gold['data'][] = $r['gold'];
$row_platinum['data'][] = $r['platinum'];
$row_silver['data'][] = $r['silver']; '';
}
$rslt = array();
array_push($rslt, $bln);
array_push($rslt, $row_gold);
array_push($rslt, $row_platinum);
array_push($rslt, $row_silver);
print json_encode($rslt, JSON_NUMERIC_CHECK);
This code will works really well with Highcharts.这段代码与 Highcharts 配合得非常好。 Thank you again @Tin Tran.再次感谢@Tin Tran。
I am not familiar php, but I think based on your goal of the JSON, this query might give you result you're after.我不熟悉 php,但我认为根据您对 JSON 的目标,此查询可能会给您带来您想要的结果。
SELECT B.year,
SUM(A.level = 'Gold') as Gold,
SUM(A.level = 'Silver') as Silver,
SUM(A.level = 'Platinum') as Platinum
FROM level AS A
INNER JOIN company_level AS B ON A.id_level = B.id_level
GROUP BY B.year
ORDER BY B.year;
result:结果:
year Gold Silver Platinum
2010 2 1 2
2011 1 0 0
2013 1 0 0
2014 0 0 1
2015 0 1 0
sqlfiddle -> http://sqlfiddle.com/#!9/59893/3 sqlfiddle -> http://sqlfiddle.com/#!9/59893/3
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