在 Python 中搜索 XML 内容

Question

I have the following XML file:

With some help of StackOverflow, I managed to achieve some of what I planned to do. Now, I want to add a search function to my script and singularly work on that sub-tree. For example, I ask the user - what ID? He enters AL2012-2015-088 . Recursively searching for this ID in a huge XML file, the script should find this ID and print the elements it has.

I used content.find("AL2012-2015-088") , but it won't work!

Answer 1

If you would switch to lxml.etree , you would be able to use the full power of XPath expressions (you would also speed things up dramatically).

Here is an example - locating the update element with a desired id and printing out the title :

from lxml import etree as ET

id_that_user_enters = "AL2012-2015-088"
tree = ET.parse("example.xml")

update = tree.xpath("//update[id = '%s']" % id_that_user_enters)[0]
print(update.findtext("title"))

Prints:

Amazon Linux 2012.03 - AL2012-2015-088: medium priority package update for gnutls

Answer 2

I believe the find command is designed to find tags as opposed to the text within the tags so you should do find on id . I'm not sure which info you need from the XML, but here is an example that gets the title.

import xml.etree.ElementTree as elt
content = elt.parse('example.xml').getroot()

def get_id_info(inputID):
    for child in content:
        if child.find('id').text == inputID:
            print child.find('title').text

get_id_info('AL2012-2014-001')

gives Amazon Linux 2012.03 - AL2012-2014-001...