MySQL从表WHERE值> 0中选择行

Question

Hey im having trouble constructing this mysql query its stumped me for about a week now im hoping someone has the answer and can help me learn!

my table looks like this:

What I want Im looking to get all of the values out of my table WHERE the username OR email = 'abc123' AND WHERE the values of attack strength defense agility etc... are > 0

So basically how could I only get rows where the values in my columns are greater than 0 and the values are associated with the correct username and email

any help would be much appreciated! im not sure if i explained this the best way but id love to help clarify!

here's what i was working with so far

SELECT Attack, Strength, Defense, Magic, Ranged, Prayer, Runecrafting, Dungeoneering, Construction, Constitution, Agility, Herblore, Thieving, Crafting, Slayer, Hunter, Mining, Smithing, Fishing, Cooking, Firemaking, Woodcutting, Farming, Summoning FROM experience WHERE email =  abc123 OR username = abc123

Answer 1

SELECT Attack, Strength, Defense, Magic, Ranged, Prayer, Runecrafting, Dungeoneering, Construction, Constitution, Agility, Herblore, Thieving, Crafting, Slayer, Hunter, Mining, Smithing, Fishing, Cooking, Firemaking, Woodcutting, Farming, Summoning FROM experience WHERE (email =  "abc123" OR username = "abc123") AND Attack > 0 AND Strength > 0 AND Defense > 0 AND *etc*

Answer 2

And why doesn't this work? where (email = 'abc123' OR username = 'abc123') and attack > 0 and strength > 0 and . . .

It works like the following if: if( (email == 'abc123' || username == 'abc123') && stength > 0)

The first parts between "()" with "||" means that at last one the conditions inside of it must be true. And && outside means that also the last condition must be true.

I also recommend you to use user ID because it's really better than user name/email

Answer 3

Your solution

SELECT Attack, Strength, Defense, Magic, Ranged, Prayer, Runecrafting, Dungeoneering, Construction, Constitution, Agility, Herblore, Thieving, Crafting, Slayer, Hunter, Mining, Smithing, Fishing, Cooking, Firemaking, Woodcutting, Farming, Summoning FROM experience WHERE (email = abc123 OR username = abc123) AND (Attack + Strength + Defense + Magic + Ranged + Prayer + Runecrafting + Dungeoneering + Construction + Constitution + Agility + Herblore + Thieving + Crafting + Slayer + Hunter + Mining + Smithing + Fishing + Cooking + Firemaking + Woodcutting + Farming + Summoning > 0);

Unfortunately, unless you have a column to sum up all the statistics, the only way to achieve you want is to manually compare all, in which case I use + to sum it up.

Answer 4

Couldn't find a way to get the data out of the database to way I wanted it so I decided it would be better to simply pull out all the data from the table and filter it using php

$stmt2 = $DB_con->prepare("SELECT * FROM experience WHERE username = :uname OR email = :email");
$stmt2->execute(array(':uname' => $_SESSION['username'], ':email' => $_SESSION['email']));
$rowExperience = $stmt2->fetch(PDO::FETCH_ASSOC);

$skills = array("Attack", "Strength", "Defense", "Magic", "Ranged", "Prayer", "Runecrafting", "Dungeoneering", "Construction",
                 "Constitution", "Agility", "Herblore", "Thieving", "Crafting", "Fletching", "Slayer", "Hunter", "Mining", "Smithing","Fishing", "Cooking", "Firemaking", "Woodcutting", "Farming", "Summoning");


           for($i = 0; $i < count($skills); $i++) {
                if(intval($rowExperience[$skills[$i]]) > 0) {
                    echo '<td style="color:grey;">' . $skills[$i] . ' - ' . $rowExperience[$skills[$i]] . '</td>';   
                }           

 }