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SQL:大于或等于基于案例条件的where子句?

[英]SQL: Greater than or equal to in where clause based on case condition?

I want to select such that if @reporteetype is 'immediate' then I would want to select rows where level is equal to 1, otherwise where level is greater than 2. 我想选择这样,如果@reporteetype'immediate'那么我想选择level 等于 1的行,否则level 大于 2。

select a, b, c, level
from table1
where col1 ='x' and                              
      CASE @reporteetype WHEN 'immediate' THEN level = '2'   
                         WHEN 'other' THEN level > 2
                         else 1 = 1
      END 

This is a simplified version of my scenario. 这是我的方案的简化版本。 I do not want to use dynamic query. 我不想使用动态查询。 I want to know if this could be done using case? 我想知道这是否可以用案例来完成?

You can do it using combinations of AND and OR conditions: 您可以使用ANDOR条件的组合来执行此操作:

SELECT
    a, b, c, level
FROM table1
WHERE
    col1 = 'x'
    AND (
        (@reporteetype = 'immediate' AND level = 2)
        OR (@reporteetype = 'other' AND level > 2)
    )

Additional reading: 补充阅读:

Catch-all Queries by Gail Shaw Gail Shaw抓住了所有的查询

Answer suggested by @Felix Pamittan is more efficient, however if you want to use CASE Expression, then it can be helpful: @Felix建议的答案Pamittan更有效,但是如果你想使用CASE Expression,那么它会有所帮助:

SELECT  a
      , b
      , c
      , level
FROM    table1
WHERE   col1 = 'x'
        AND ( ( CASE WHEN @reporteetype = 'immediate' THEN '2'
                END ) = level
              OR ( CASE WHEN @reporteetype = 'other' THEN '2'
                   END ) > level
            )

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