在子查询中按日期排序？

Question

I'm using Oracle 11g, come across the situation to order the data based on sub-query.

Assume having the two tables STATUS_TABLE and TXN_TABLE . I want to short the TXN_TABLE based on the STATUS_TABLE 's DATE_INS field.

Below is the sample query,

SELECT ID
FROM STATUS_TABLE
WHERE STATUS = 'Pass'
ORDER BY DATE_INS DESC

This query returns me a list of ID's in descending order based on the DATE_INS. So the above query has been extended little bit for TXN_TABLE as follows

SELECT *
FROM TXN_TABLE
WHERE ID IN (SELECT ID FROM STATUS_TABLE
             WHERE STATUS = 'Pass'
             ORDER BY DATE_INS DESC)

which gives me:

ORA-00907: missing right parenthesis

I gone through the document, they where telling that it is not possible to make a order class at sub-query. so is there any workaround for this scenario to make it work?

Comment on below, if you need any more details on this. Any help would be appreciated!

Answer 1

Maybe you can try this

SELECT tmp.* FROM
    (SELECT tx.*, st.DATE_INS AS DATE_INS_ST
    FROM TXN_TABLE tx, STATUS_TABLE st
    WHERE tx.ID = st.ID AND st.STATUS = 'Pass') tmp
ORDER BY DATE_INS_ST DESC

Answer 2

Ordering the subquery will give no ordering on the final result; you could rewrite your query as:

SELECT *
FROM TXN_TABLE
    INNER JOIN STATUS_TABLE
USING(ID)
WHERE STATUS='Pass'
ORDER BY DATE_INS DESC

assuming, as rightly oberved by jarlh, that your ID columns can not have duplicate values