如果在 html 表中选中复选框，那么我想在按下更新按钮时更新该行的值

Question

this is my fetched table and i have added check box to every row now i want to update this table if specific field is checked so kindly suggest me something`while($record=mysql_fetch_array($res)){

echo "<tr align='center'>";
echo "<td>".$record['YourName']."</td>";
echo "<td>".$record['FatherName']."</td>";
echo "<td>".$record['RegNum']."</td>";
echo "<td>".$record['Gender']."</td>";
echo "<td name='$i' >".$record['MobileNumber']."</td>";

echo "<td>".$record['Password']."</td>";
echo "<td>".$record['specialist']."</td>";
echo "<td>".$record['area']."</td>";
echo "<td>".$record['building']."</td>";
echo "<td>".$record['room']."</td>";
echo "<td><input type='checkbox' name='$i' value='Bike' align='center'></td>";
echo "</tr>";

$i++;

Here is fetched data and the check box.

Answer 1

your design need to be changed, do something like

echo "<tr align='center'>";
echo "<td>".$record['YourName']."</td>";
echo "<td>".$record['FatherName']."</td>";
echo "<td>".$record['RegNum']."</td>";
echo "<td>".$record['Gender']."</td>";
echo "<td name='$i' >".$record['MobileNumber']."</td>";

echo "<td>".$record['Password']."</td>";
echo "<td>".$record['specialist']."</td>";
echo "<td>".$record['area']."</td>";
echo "<td>".$record['building']."</td>";
echo "<td>".$record['room']."</td>";
echo "<td><a href='edit.php?id={you id for record}'>Edit</a></td>";
echo "</tr>";

it will look like

Answer 2

jQuery is your solution. Take a look at this page

You can implement it like in here

$(document).ready(function() { //set initial state. $('#textbox1').val($(this).is(':checked')); $('#checkbox1').change(function() { if($(this).is(":checked")) { var returnVal = confirm("Are you sure?"); $(this).attr("checked", returnVal); } $('#textbox1').val($(this).is(':checked')); }); });

Answer 3

Since, Database Table structure is not provided. I am assuming : Primary Key & Auto-Increment column name as user_id . (Change it, if you having other column name).

<form method='POST' action='approve.php'>
    <table>
        <?
        $i=1;
        while($record=mysql_fetch_array($res)){
            echo "<tr align='center'>";
                echo "<td>".$record['YourName']."</td>";
                echo "<td>".$record['FatherName']."</td>";
                echo "<td>".$record['RegNum']."</td>";
                echo "<td>".$record['Gender']."</td>";
                echo "<td name='$i' >".$record['MobileNumber']."</td>";

                echo "<td>".$record['Password']."</td>";
                echo "<td>".$record['specialist']."</td>";
                echo "<td>".$record['area']."</td>";
                echo "<td>".$record['building']."</td>";
                echo "<td>".$record['room']."</td>";
                // Pay Attention Here in this checkbox. 
                echo "<td><input type='checkbox' name='Approve[]' value='".$record['user_id']."' align='center'></td>";
            echo "</tr>";
        $i++;
        }?>
    </table>
</form>

approve.php

<?php
$countApprovedCheckbox = sizeof($_POST['Approve']);

for($i=0;$i<$countApprovedCheckbox;$i++) {

    $userID = $Approve[$i];

    $query = "UPDATE TableName SET ApproveColumnName='Approve' WHERE user_id='$userID'";
    //Execute Your Query Here.

}
?>