如何使用模式重命名文件夹中的所有文件

Question

I have a bunch of files like:

bla.super.lol.S01E03.omg.bbq.mp4
bla.super.lol.S01E04.omg.bbq.mp4
bla.super.lol.s03e12.omg.bbq.mp4

I need to rename them all like:

s01e03.mp4
s01e04.mp4
s03e12.mp4

I've tried to do it with for file in *; do mv $file ${file%%\\.omg*}; done for file in *; do mv $file ${file%%\\.omg*}; done for file in *; do mv $file ${file%%\\.omg*}; done but it removes only part after S01E01, not before it so please, help

Answer 1

许多Linux都提供了一个很好的命令行工具，称为“ rename ，它使用了Perl正则表达式：

rename 's/.*\.(\w+\d)\..*/$1.mp4/;y/A-Z/a-z/' *.mp4

Answer 2

Simple Perl script that tries to parse out the episode information, skips files where it can't find them.

#!perl 

use strict;
use warnings; 

use File::Copy qw(move);

foreach my $file ( glob('*.mp4') ) {
   my ($info) = $file =~ m/([sS]\d+[eE]\d+)/;
   next unless $info;

   my $new_filename = lc $info . ".mp4";    
   move $file, $new_filename
      or die "$!";
}

Answer 3

A pure Bash solution :

for f in *.mp4; do
    IFS=. read -r _ _ _  s _ <<< "$f"
    mv -- "$f" "${s,,}.mp4"
done

To test it, I created the following tree:

tree
.
├── bla.super.lol.S01E03.omg.bbq.mp4
├── bla.super.lol.S01E04.omg.bbq.mp4
└── bla.super.lol.s03e12.omg.bbq.mp4

0 directories, 3 files

Let's put a printf before mv to be sure about the changes:

mv -- bla.super.lol.S01E03.omg.bbq.mp4 s01e03.mp4
mv -- bla.super.lol.S01E04.omg.bbq.mp4 s01e04.mp4
mv -- bla.super.lol.s03e12.omg.bbq.mp4 s03e12.mp4

Looks good. The season part is extracted, and lower-cased as requested.

Answer 4

If your filenames are always dot-separated and the SExxEmm part is always the 4th one, then I'd do it with awk:

for file in *; do 
    mv $file $(echo $file | awk -F. '{print $4 "." $NF}');
done

awk -F. splits the filename at the dots apart and then prints the 4th and last field.

To do a "dry run" (ie show the commands instead of executing them), prepend them with echo :

for file in *; do 
    echo mv $file $(echo $file | awk -F. '{print $4 "." $NF}');
done