在java中使用正则表达式从字符串中提取特定数字

Question

Here is my string

INPUT:

22 TIRES (2 defs)

1 AP(PEAR + ANC)E (CAN anag)

6 CHIC ("SHEIK" hom)

EXPECTED OUTPUT:

22 TIRES

1 APPEARANCE

6 CHIC

ACTUAL OUTPUT :

TIRES

APPEARANCE

CHIC

I tried using below code and got the above output.

String firstnames =a.split(" \\(.*")[0].replace("(", "").replace(")", "").replace(" + ",
                        "");

Any idea of how to extract along with the numbers ? I don't want the numbers which are after the parentheses like in the input " 22 TIRES (2 defs)". I need the output as "22 TIRES" Any help would be great !!

Answer 1

I would use a single replaceAll function.

str.replaceAll("\\s+\\(.*|\\s*\\+\\s*|[()]", "");

DEMO

• \\\\s+\\\\(.* , this matches a space and and the following ( characters plus all the remaining characters which follows this pattern. So (CAN anag) part in your example got matched.

• \\\\s*\\\\+\\\\s* matches + along with the preceding and following spaces.

• [()] matches opening or closing brackets.

• Atlast all the matched chars are replaced by empty string.

Answer 2

I am doing it bit differently

String line = "22 TIRES (2 defs)\n\n1 AP(PEAR + ANC)E (CAN anag)\n\n6 CHIC (\"SHEIK\" hom)"; 
String pattern = "(\\d+\\s+)(.*)\\(";
Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(line);
while (m.find()) {
    String tmp = m.group(1) + m.group(2).replaceAll("[^\\w]", "");
    System.out.println(tmp);
}

Ideone Demo