如何使用C＃在Ms Access中插入当前日期/时间

Question

I have tried almost everything to insert the current date and time in to MS Access database using c# and nothing seems to work. The table structure looks like

ID(Primary Key) Est_ID(Number)  saveName(Text) userName(Text) timestamp(Date/Time)

The code looks like

OleDbConnection conn = new OleDbConnection(connectionString);
conn.Open();

DateTime today = DateTime.Today;
DateTime time= DateTime.Now;
string name = Request.Form["saveName"];

string my_querry = "INSERT INTO TABLENAME (userName, Est_id,saveName,timestamp) VALUES(@userName,@Est_id,@saveName,@timestamp)";

OleDbCommand cmd = new OleDbCommand(my_querry, conn);

cmd.Parameters.AddWithValue("@userName", userName);
cmd.Parameters.AddWithValue("@Est_id", est_index);
cmd.Parameters.AddWithValue("@saveName", name);
cmd.Parameters.AddWithValue("@timestamp",time);

cmd.ExecuteNonQuery();

I have tried formatting. I added # but nothing seems to work. This is really frustrating since I have spent more than a day now getting this to work. What am I doing wrong?

Answer 1

OleDB/Access requires you to explicitly set the data type for date/time values.

var param = cmd.Parameters.AddWithValue("@timestamp",time);
param.OleDbType = OleDbType.Date;

Answer 2

OleDbConnection conn = new OleDbConnection(connectionString);
conn.Open();

string name = Request.Form["saveName"];

string my_querry = "INSERT INTO TABLENAME (userName, Est_id,saveName,timestamp) VALUES(@userName,@Est_id,@saveName,Now())";

OleDbCommand cmd = new OleDbCommand(my_querry, conn);

cmd.Parameters.AddWithValue("@userName", userName);
cmd.Parameters.AddWithValue("@Est_id", est_index);
cmd.Parameters.AddWithValue("@saveName", name);


cmd.ExecuteNonQuery();

Answer 3

According from this link https://support.office.com/en-us/article/Format-the-date-and-time-field-in-Access-47fbbdc1-52fa-416a-b8d5-ba24d881b698

You may need to check on your column setting in database that It's already set Format of timestamp column to Genaral Date to match with DateTime.Now in C#.

Also, You need to check that output of System.DateTime and your database time format is 12Hours system or 24Hours system.

Hope this information can help you.

Answer 4

If you are using Tortuga Chain:

static AccessDataSource s_DataSource = new AccessDataSource(connectionString); //one per application

---

DateTime today = DateTime.Today;
DateTime time= DateTime.Now;
string name = Request.Form["saveName"];

s_DataSource.Insert("TABLENAME", new {@username = userName, @Est_id = est_index,@saveName = name,@timestamp = time}).Execute();

Answer 5

I know this post is a little old but it could help someone. Since this morning I am confronted with this problem. And I finally found the solution.

The value that DateTime.Now sends to the database is in the form {dd / mm / yyyy hh: mm: ss} and what happens, I think, is that access does not recognize { } .

So to solve the problem just convert the date to string before assigning it to the parameters:

cmd.Parameters.AddWithvalue("@timestamp", time.ToString());

Or

cmd.Parameters.AddWithvalue("@timestamp", oleDbType.Date).Value=time.ToString());

That work very well for me