以文件名作为参数的shell脚本，并从Unix / Linux / Ubuntu中pwd上方的每个目录中删除此文件

Question

my shell script is as follows.

if [ $# -eq 0 ]
then
    echo "pass the file name"
    exit
 fi
fl=$1
ch=1
h=/home

while [ $ch -eq 1 ]
do
    cd ..
    p=`pwd`
    echo "$p/$fl"
    rm `echo "$p/$fl"` 2> /dev/nullif [ $p = $h ]
    then
            ch=0
    fi
done

but when executing shows a syntax error. line16: syntax error near unexpected token then' line 16: then'

What is the mistake in this script?

Answer 1

You misplaced if the script.

if [ $# -eq 0 ]
then
    echo "pass the file name"
    exit
fi

fl=$1
ch=1
h=/home

while [ $ch -eq 1 ]
do
    cd ..
    p=`pwd`
    echo "$p/$fl"
    rm `echo "$p/$fl"` 2> /dev/null
    if [ $p = $h ]
    then
            ch=0
    fi
done