如何使用单个查询和 PHP 显示此特定 mySQL 表的行？

Question

I have the following table in mySQL. My question is how can I show the last 2 days (yesterday and 2 days ago) unique_visitors, pageviews etc with a single query?

I want this to be dynamically, meaning to no use dates such as where date ='2016-05-02'

The output will be through PHP.

id date       unique_visitors pageviews
 4 2016-05-02            3108     27166
 3 2016-05-01            2189     16848
 2 2016-04-30            2475     20568
 1 2016-04-29            2733     22877

Answer 1

Possible duplicate: get 2 days ago query in mysql

WHERE date BETWEEN 
    DATE_SUB(DATE(NOW()), INTERVAL 2 DAY)
    AND DATE_SUB(DATE(NOW()), INTERVAL 1 DAY) 

Answer 2

您可以使用以下动态查询来获取最近 3 天的工资

SEKECT *FROM TABLENAME WHERE DATE_COLUMN >= DATE_ADD(CURDATE(), INTERVAL -2 DAY);