如何选择外键子行早于特定日期的所有父行？

Question

I have a table of orders and a table of updates, which are connected to orders by a one (order) to many (updates) relationship. I am trying to select all orders which have not been updated in the last 24 hours.

Here's the updates table (off the top of my head):

id INT PRIMARY KEY AUTO INCREMENT,
order_id INT NOT NULL ,
update VARCHAR(255) NOT NULL,
created_at TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
foreign key (order_id) REFERENCES orders(id)

And the orders table:

id INT PRIMARY KEY AUTO INCREMENT,
enabled TINYINT(1) NOT NULL DEFAULT 0,
reference VARCHAR(10) NOT NULL,
created_at TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP

How do I return all orders that are enabled, and which have either no update yet or the most recent update being older than one day? (It's fine for me to use either pure MySQL, or, preferably, Laravel's Eloquent ORM.)

Thank you.

Answer 1

I'd do a NOT EXISTS , to return orders that doesn't have a recent update:

select * from orders o
where enabled = 1
  and not exists (select 1 from updates u
                  where u.order_id = o.id
                    and u.created_at >= NOW() - INTERVAL 1 DAY)