如何从表SQL获取不存在的记录？

Question

Sorry if my question was stupid or basic.I trying to get not exist id records from db. But it is showing all records.

---------------------+
id  |  name  |  age  |
---------------------+
 1  |   ase  |   33  |
 3  |   ase  |   33  |
 4  |   ase  |   33  |
 5  |   ase  |   33  |
 7  |   ase  |   33  |
 9  |   ase  |   33  |
---------------------+

i tried something like this

SELECT * FROM tablename WHERE id NO IN ('1','2','4','5','6','7') but it showing all records. In this given query id 2,6 are not exist in table show i need to show them as result. please some one help me to solve this. thanks

expecting output like

----------------------+
id not exist in table |
----------------------+
          2           |
          6           |
----------------------+

from the given IN statement this ID are not exist in TABLE something like this. I need to show id which are not exist in table as result.

Answer 1

You need to use a (derived) table of values. Here is a solution using left join instead of not in :

select n.n
from (select 1 as n union all select 2 union all select 4 union all select 5 union all
      select 6 union all select 7
     ) n left join
     tablename t
     on t.id = n.n
where t.id is null;