Python selenium 代码不起作用

Question

Why the looping is not working after opening the first element as per the xpath ? And i am getting the below exception

 raise exception_class(message, screen, stacktrace) selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element:{"method":"xpath","selector":"//[@id='searchresults']/tbody/tr[2]/td[1]"} Stacktrace: at FirefoxDriver.prototype.findElementInternal_ (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/driver-component.js:10723) at FirefoxDriver.prototype.findElement (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/driver-component.js:10732) at DelayedCommand.prototype.executeInternal_/h (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/command-processor.js:12614) at DelayedCommand.prototype.executeInternal_ (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/command-processor.js:12619) at DelayedCommand.prototype.execute/< (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/command-processor.js:12561)

Code:

from selenium import webdriver
from texttable import len
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
driver=webdriver.Firefox()
driver.get('https://jobs.ericsson.com/search/')
driver.maximize_window()
driver.find_element_by_css_selector('[type="text"][id="keywordsearch-q"]').send_keys('Python')
driver.find_element_by_css_selector('[class="btn"][type="submit"]').click()
i=len("//*[@id='searchresults']/tbody/tr/td")
for j in range(1,i+1):
   driver.find_element_by_xpath("//*[@id='searchresults']/tbody/tr[%d]/td[1]"%j).click()
   print driver.find_element_by_id("job-title").text
   driver.back()
   continue

Question 2: Why the length of the list is getting displayed as 12 but they have only 5 herf elements in it ?

from selenium import webdriver
from texttable import len
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
driver=webdriver.Firefox()
driver.delete_all_cookies()
driver.get('https://jobs.ericsson.com/search/')
driver.maximize_window()
driver.find_element_by_css_selector('[type="text"][id="keywordsearch-q"]').send_keys('Python')
driver.find_element_by_css_selector('[class="btn"][type="submit"]').click()
#currenturl = driver.current_url
pages=driver.find_elements_by_css_selector('a[rel="nofollow"]')
print pages
print 'Its working'
pages1=[]
for page1 in pages:
  pages1.append(page1.get_attribute('href'))
  print int(len(pages1))

Question 3: How to get the elements under html tags

a.How to get the 1-25 and 104 separately under the b tag ?

Please refer the URL: https://jobs.ericsson.com/search/?q=Python (result section getting displayed at the bottom of the page)

<div class="paginationShell clearfix" lang="en_US" xml:lang="en_US">
<div class="pagination well well-small">
<span class="pagination-label-row">
<span class="paginationLabel">
 Results 
 <b>1 – 25</b>
   of 
 <b>104</b>
 </span>

b.How to get the Job id from the html ?

 <div class="job">
<span itemprop="description">
<b>Req ID:</b>
 128378
<br/>
<br/>

Answer 1

Please try following:

for job in range(len(driver.find_elements_by_class_name('jobTitle-link'))):
    driver.implicitly_wait(5)
    driver.find_elements_by_class_name('jobTitle-link')[job].click()
    print driver.find_element_by_id("job-title").text
    driver.back()

Answer 2

This may or may not help you, but based on my own experience, I typically run into this error when my page hasn't fully loaded. Adding a time.sleep(1) before searching for the element usually fixes the problem for me (if the code is correct).

import time

#Skip your other code

for j in range(1,i+1):
   time.sleep(1)
   driver.find_element_by_xpath("//*[@id='searchresults']/tbody/tr[%d]/td[1]"%j).click()
   print driver.find_element_by_id("job-title").text
   driver.back()
   continue

Answer 3

Here is a solution that works, the idea is not to click on each link rather store the url in a list and then navigate to it:

from selenium import webdriver
from texttable import len
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait

driver=webdriver.Firefox()
driver.get('https://jobs.ericsson.com/search/')
driver.maximize_window()
driver.find_element_by_css_selector('[type="text"][id="keywordsearch-q"]').send_keys('Python')
driver.find_element_by_css_selector('[class="btn"][type="submit"]').click()

#To further process preserve the current url    
currenturl = driver.current_url
#Get all the elements by class name
jobs  = driver.find_elements_by_class_name('jobTitle-link')
jobslink = []
#Get hyperlink urls from the jobs elements
#This way we avoid clicking each link and going back to the previous page
for job in jobs:
    jobslink.append(job.get_attribute('href'))
#Get each element page  
for job in jobslink:
    driver.get(job)
    print driver.find_element_by_id("job-title").text