可以在子类的方法内部使用“ super”来调用相应的父类方法而无需直接引用吗？

Question

I came across a usage of "super" in a tutorial that seemed strange. super() is used inside the method get() of the subclass to call the method get() of the superclass without using any accessor notations. Would that work? If yes, where can I find more references about it?

Edit:

class Answer {
  constructor(value) {
    this._val = value;
  }
  get() {
    return this._val;
  }
}

class FirmAnswer extends Answer {
  constructor(value) {
    super(value);
  }

  get() {
    return super() + '!!';
  }
}
var luckyAnswer = new FirmAnswer(7);
luckyAnswer.get();

Thanks @FlexiKling and @sorenymous for typing the code :)

Answer 1

No, direct super calls (without a property) are only allowed in constructors, and constitute syntax errors everywhere else. It needs to be super.get() .

The tutorial you are referencing is from 2013. In the earlier versions of the class syntax proposal, this form was indeed possible. However, it was removed in Draft Rev 28 (October 14, 2014 ) :

super without an immediately following property specifier is now illegal in all MethodDefinition (no more implicit super using current method name)

Answer 2

I tested your code and it produced a syntax error.

class Answer {
  constructor(value) {
    this._val = value;
  }
  get() {
    return this._val;
  }
}

class FirmAnswer extends Answer {
  constructor(value) {
    super(value);
  }

  get() {
    return super() + '!!';
  }
}
var luckyAnswer = new FirmAnswer(7);
luckyAnswer.get();

Console Output:

Uncaught SyntaxError: 'super' keyword unexpected here