如何在python中暂停脚本以防止同时检测2个传感器？

Question

I have this function in a python script that detects 2 vibrations sensors, the problem is the sensors are very sensitive so usually when one is hit they are both detected which gives me a false reading. How would I stop them both from being detected at the same time? I want to detect whichever was first. This is what I have tried -

#!/usr/bin/env python
import RPi.GPIO as GPIO
from time import sleep

def setup():
    GPIO.setmode(GPIO.BOARD)         
    GPIO.setup(KnockPin, GPIO.IN, pull_up_down=GPIO.PUD_UP)
    GPIO.setup(ShockPin, GPIO.IN, pull_up_down=GPIO.PUD_UP)

def shock():
    print('shock')

def knock():
    print('knock')

def register_callbacks():
    if GPIO.add_event_detect(ShockPin, GPIO.FALLING, callback=shock, bouncetime=5000):
        sleep(5)
    elif GPIO.add_event_detect(KnockPin, GPIO.FALLING, callback=knock, bouncetime=5000):
        sleep(5)

if __name__ == '__main__':
    try:
        setup()
        register_callbacks()

Answer 1

Just a suggestion, I don't have the setup to test it. Save the time of the last event (using datetime ), and then check if the last event is more than 5 seconds ago.

import datetime
sensor_delay = 5 #delay in seconds
last_event = datetime.datetime.now()

def shock():
    global last_event
    if datetime.datetime.now() > last_event + datetime.timedelta(seconds=sensor_delay):
        print ('shock')
        last_event = datetime.datetime.now()

def knock():
    global last_event
    if datetime.datetime.now() > last_event + datetime.timedelta(seconds=sensor_delay):
        print('knock')
        last_event = datetime.datetime.now()