[英]Trying to 'free' a linked list in C
I've started C programming yesterday and tried to implement a linked list (just really really basic).我昨天开始了 C 编程,并试图实现一个链表(只是非常基本的)。
So far everything works pretty fine except for freeing a list.到目前为止,除了释放列表之外,一切都很好。
First, here's my code:首先,这是我的代码:
#include <stdio.h>
#include <stdlib.h>
/*
* Struct for elements of the linked list
*/
struct element {
struct element* nextelement;
int value;
};
/*
* Struct for a list itself
*/
struct liste {
struct element* headelement;
};
/*
* Function to create new elements
*/
struct element* createelement(int value) {
struct element* dummyelement = malloc(sizeof(struct element));
dummyelement->nextelement = NULL;
dummyelement->value = value;
return dummyelement;
}
/*
* Function to create new (empty) lists
*/
struct liste* createlist() {
struct liste* dummylist = malloc(sizeof(struct liste));
dummylist->headelement = NULL;
return dummylist;
}
/*
* Add an element to a given list
*/
void addelement(struct liste* liste, int value) {
struct element* dummyelement = createelement(value);
if (liste->headelement == NULL) {
liste->headelement = dummyelement;
} else {
struct element* iterelement = liste->headelement;
while (iterelement->nextelement != NULL) {
iterelement = iterelement->nextelement;
}
iterelement->nextelement = dummyelement;
}
}
/*
* Plot the elements of a given list
*/
void plotlist(struct liste* liste) {
if (liste->headelement != NULL) {
struct element* iterelement = liste->headelement;
printf("%d\n", iterelement->value);
while (iterelement->nextelement != NULL) {
iterelement = iterelement->nextelement;
printf("%d\n", iterelement->value);
}
} else {
printf("Where is my head?\n");
}
}
/*
* This should completely remove the list, but it fails...
*/
void removelist(struct liste* liste) {
if (liste->headelement != NULL) {
struct element* iterelement = liste->headelement;
struct element* nextelement = iterelement->nextelement;
free(iterelement);
while (nextelement != NULL) {
iterelement = nextelement;
nextelement = iterelement->nextelement;
free(iterelement);
}
}
free(liste);
}
int main(void) {
/*
* Creates a new list
* Plots the (empty) list
* Adds two elements to the list
* Plots the list again
* Removes the list
* Last plot shouldn't really happen, but it does.
*/
struct liste* mylist = createlist();
printf("First plot.\n");
plotlist(mylist);
addelement(mylist, 1);
addelement(mylist, 2);
printf("Second plot.\n");
plotlist(mylist);
removelist(mylist);
printf("Third plot.\n");
plotlist(mylist);
return 0;
}
I get the following output:我得到以下输出:
First plot.
Where is my head?
Second plot.
1
2
Third plot.
33
Well, obviously the '33' is my problem.好吧,显然“33”是我的问题。 I really don't know how this can be the output... Furthermore I don't know why my 'removelist' isn't working properly.
我真的不知道这怎么可能是输出......此外我不知道为什么我的“removelist”不能正常工作。 I am freeing everything which I've allocated with 'malloc'.
我正在释放我用'malloc'分配的所有东西。 What am I doing wrong?
我究竟做错了什么?
You do not check inside plotlist
whether your list actually exists.您不会在
plotlist
内部检查您的列表是否确实存在。 You directly try to access the headelement
.您直接尝试访问
headelement
。 Better do the following:最好做到以下几点:
void plotlist(struct liste* liste) {
if(liste == NULL){
printf("This list does not even exist.\n");
}
else if (liste->headelement != NULL) {
// ...
} else {
printf("Where is my head?\n");
}
}
As removelist
also frees the list structure as such, you better set the pointer to NULL
inside main.由于
removelist
也释放了列表结构,因此最好在 main 中将指针设置为NULL
。 Otherwise you get undefined behaviour upon accessing freed memory.否则,访问释放的内存时会出现未定义的行为。
int main(void) {
// ...
removelist(mylist);
mylist = NULL;
printf("Third plot.\n");
plotlist(mylist);
return 0;
}
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