MySQL：选择列是给定字符串一部分的行

Question

I search for a way to find a part of a given string in my table entries. The field is varchar in table.

Search for

/brands/brand/actona/kitchen-article/item/01945

and want to find this row:

/brands/brand/actona/$

- or maybe this row

/brands/brand/actona/kitchen-$

Is there a way to solve this issue? The problem is that the table have at least 57k entries. I import the data from a old (too large) nginx-config file which are all permanent redirects.

Updated: What I need a roughly the opposite of "LIKE", because just a part of the string i search for is stored in table with a wildcard ($), that can match also another string that starts with the same. /brands/brand/actona/$ can match /brands/brand/actona/123 but also /brands/brand/actona/abc/def .

So when I search for /brands/brand/actona/abc/def or even /brands/brand/actona/abc/def/xyz it need to match the row /brands/brand/actona/$

I actually try to outsource 57k permanent redirects from a nginx.config file to avoid checking a 6MB config file on each request.

I'm so sorry for my terrible english :(

Answer 1

Perhaps something like

SELECT * FROM TABLE
WHERE '/brands/brand/actona/kitchen-article/item/01945'
LIKE CONCAT('%', URLCOLUMN, '%');

Answer 2

How about something like this?

SELECT * FROM table
WHERE
column REGEXP '(/[a-zA-Z0-9-]+)+\$?'