[英]SQL select first 3 records from given date
I have two tables namely Customers and Transactions.我有两个表,即客户和交易。 There is offer that starts from the 1st of the current month.
有从当月 1 日开始的报价。
Customers Table客户表
Customer_ID Email Created_Date
1 abc@g.com 2015-08-14 12:25:55
2 xyz@s.com 2016-01-23 18:16:34
.
.
n ags@h.com 2016-05-05 23:25:43
Transactions Table交易表
Trans_ID Customer_ID Trans_Date Amount
asd654qwe 2 2015-09-25 13:15:56 1200
dfg123xcv 56 2016-03-22 21:26:52 100
.
.
rty321cvb 4125 2016-05-05 08:42:06 500
I need to select only first 3 transactions of all customers after 1st of current month and then if the customer is new his first transaction is eligible for 100% cashback.我只需要选择当月 1 日之后所有客户的前 3 笔交易,然后如果客户是新客户,他的第一笔交易有资格获得 100% 现金返还。 New customers second and third transaction is eligible for 50% cashback.
新客户第二次和第三次交易有资格获得50%的现金返还。 If customer is old his first and second transaction after 1st of this month is eligible for 50% cashback each.
如果客户老了,他在本月 1 日之后的第一次和第二次交易有资格获得 50% 的现金返还。
I need to generate the report on daily basis for transaction done yesterday and share it to accounts team.我需要每天为昨天完成的交易生成报告,并将其分享给客户团队。 SQL is not my primary task and due to shortage i need to look into it.
SQL 不是我的主要任务,由于短缺,我需要研究它。 I am doing all this manually using excel.
我正在使用 excel 手动完成所有这些操作。 It is very time consuming.
这是非常耗时的。 Can anyone please let me know a query that could give me the expected results?
任何人都可以让我知道一个可以给我预期结果的查询吗?
Expected Result预期结果
c.Email c.Created_Date t.Trans_ID t.Trans_Date t.Amount Offer_Type
record record record record record First
record record record record record Repeate
record record record record record Repeate
Is this what you're looking for?这是你要找的吗?
SET @limit3 := 0, @cust := '';
--outer query determines offer type and limits the offer to three transactions per customer
SELECT Email, Created_Date, Trans_ID, Trans_Date, Amount
CASE WHEN Created_Date > First_Day THEN 'First'
ELSE 'Repeate'
END CASE AS Offer_Type,
@limit3 := if (@cust = Customer_ID, @limit3 + 1, 1) AS rowcount,
@cust := Customer_ID
--Inner query selects applicable fields, creates First_Day field,
--filters it to transactions done yesterday
FROM
(
SELECT c.Email, c.Created_Date, t.Trans_ID, t.Trans_Date, t.Amount, c.Customer_ID
DATE_ADD(LAST_DAY(c.Created_Date), interval 1 DAY), interval -1 MONTH) as First_Day
FROM Customers c
JOIN Transactions t
ON c.Customer_ID = t.Customer_ID
WHERE DATE(Trans_Date) = SUBDATE(NOW(), 1)
) AS sub
GROUP BY c.Customer_ID
HAVING rowcount <= 3
ORDER BY c.Created_Date
Sort of convoluted to do in mysql在 mysql 中要做的事情有点复杂
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