在python中第二次出现后删除'/'的所有出现

Question

I have a URL string which is https://example.com/about/hello/

I want to split string as 'https://example.com', 'about' ,'hello'

How to do this ??

Answer 1

Use the urlparse to correctly parse a URL:

import urlparse

url = 'https://example.com/about/hello/'
parts = urlparse.urlparse(url)
paths = [p for p in parts.path.split('/') if p]

print 'Scheme:', parts.scheme       # https
print 'Host:', parts.netloc         # example.com
print 'Path:', parts.path           # /about/hello/
print 'Paths:', paths               # ['about', 'hello']

At the end of the day, the information you want are in the parts.scheme , parts.netloc and paths variables.

Answer 2

You may do this :

1. First split by '/'
2. Then join by '/' only before the 3rd occurance

Code:

text="https://example.com/about/hello/"
groups = text.split('/')
print( "/".join(groups[:3]),groups[3],groups[4])

Output:

https://example.com about hello

Answer 3

Inspired in Hai Vu's answer . This solution is for Python 3

from urllib.parse import urlparse

url = 'https://example.com/about/hello/'
parts = [p for p in urlparse(url).path.split('/') if p]
parts.insert(0, ''.join(url.split('/')[:3]))

Answer 4

There are lots of ways to do this. You could use re.split() to split on a regular expression, for instance.

>>> import re
>>> re.split(r'\b/\b', 'https://example.com/about/hello/')
['https://example.com', 'about', 'hello']

re is part of the standard library, documented here. https://docs.python.org/3/library/re.html#re.split The regex itself uses \\b which means a boundy between a "word" character and a "non-word" character. You can use regex101 to explore how it works. https://regex101.com/r/mY8fV8/1