[英]What is the difference in insertion to std::unordered_map with [] and insert()
I want to add unordered_map
to my app to store values as <string,object>
pairs. 我想将unordered_map
添加到我的应用中以将值存储为<string,object>
对。 I wanted to add element to map in function, return pointer to this object, do some logic and later retrieve this value. 我想添加元素以映射到函数中,返回指向该对象的指针,执行一些逻辑,然后再检索此值。
Unfortunately I cannot do as planned, because it looks like my reference is loosing somehow connection. 不幸的是,我无法按计划进行,因为我的参考似乎失去了某种联系。 This is how insertion is currently done: 当前是这样完成插入的:
std::unordered_map<std::string, EdgeS> edges;
// Some extra stuff
EdgeS* Node::insertEdge(Node* to)
{
EdgeS edge = edges[to->name];
if(!edge.to)
edge.to = to;
edge.frequency++;
edge.packets_number++;
return &edge;
}
As you can see I am using operator[] , but when later I am trying to use this map's object it looks like it is recreated and everything I've done on it has no effect. 如您所见,我正在使用operator [] ,但是稍后我尝试使用此地图的对象时,看起来好像已重新创建它,而我对此所做的一切都没有效果。
I've been thinking also about insert , but I am not sure about difference. 我也一直在考虑insert ,但是我不确定差异。 With operator good thing is that it doesn't matter if object exists or not I can still have reference to it. 使用运算符的好处是,对象是否存在无关紧要,我仍然可以引用它。 But apparently I cannot do anything with this object. 但是显然我不能用这个对象做任何事情。 So what is better in this case? 那么在这种情况下哪个更好?
it looks like my reference is loosing somehow connection 看来我的参考资料以某种方式失去了联系
You're not using a reference. 您没有使用参考。 You're making a copy: 您正在复制:
EdgeS edge = edges[to->name];
If you want to use a reference, edge
should have type EdgeS &
. 如果要使用参考, edge
类型应为EdgeS &
。
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