[英]Reading text from a file using fscanf()
guys i want to read the text from my file and assign every character to a single element of the array伙计们,我想从我的文件中读取文本并将每个字符分配给数组的单个元素
char A[1000];
FILE * fpointer;
fpointer=fopen("text.txt","r");
i=0;
while(!feof(fpointer))
{
fscanf(fpointer,"%c",&A[i]);
i=i+1;
}
fclose(fpointer);
for (i=0;i<100;i++)
{
printf("%c",A[i]);
}
return 0;
but the problem is that the output is some weird symbols instead of the file's text which is "This is just a test".Why is that happening ?但问题是输出是一些奇怪的符号,而不是文件的文本,即“这只是一个测试”。为什么会这样?
Possible reasons include:可能的原因包括:
fopen
failed to open the specified file. fopen
未能打开指定的文件。 Fix by checking the return value of fopen
.通过检查fopen
的返回值来修复。i
.通过打印从零开始到i
所有内容来修复。Corrected code snippet:更正的代码片段:
int i = 0, j = 0;
char A[1000];
FILE* fpointer;
fpointer = fopen("text.txt", "r");
if(!fpointer)
{
fputs("fopen failed! Exiting...\n", stderr);
exit(-1); /* Requires `stdlib.h` */
}
while(fscanf(fpointer, "%c", &A[i]) != EOF)
{
i = i + 1;
}
fclose(fpointer);
for (j = 0; j < i; j++){
printf("A[%d] = '%c'\n", j, A[j]);
}
To expand on the points by @Cool Guy :要扩展@Cool Guy的观点:
In case your files do not contain the null character , you can avoid using another variable to store the number of characters read.如果您的文件不包含空字符,您可以避免使用另一个变量来存储读取的字符数。 If you null terminate your read in characters, you can just print them directly as a string.如果 null 终止读取字符,则可以直接将它们打印为字符串。
You have to make sure that A can hold enough characters.您必须确保 A 可以容纳足够的字符。 If you expect at most 1000 characters, make sure that A has a size of 1001 bytes to contain the terminating NUL character.如果您期望最多 1000 个字符,请确保 A 的大小为 1001 个字节以包含终止 NUL 字符。
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv)
{
char A[1001] = { 0 }; /* init to NUL, expect at most 1000 chars */
int i;
FILE *fpointer;
fpointer=fopen("text.txt","r");
if(!fpointer) {
perror("Error opening file"); /* print error message */
exit(-1); /* Requires `stdlib.h` */
}
/* read all characters from fpointer into A */
for (i=0; fscanf(fpointer, "%c", &A[i]) != EOF; i++);
fclose(fpointer);
printf("%s\n",A); /* print all characters as a string */
/* alternatively, loop until NUL found */
for (i=0; A[i]; i++)
printf("%c", A[i]);
printf("\n");
return 0;
}
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