如何从python中的格式化字符串中剪切子字符串？

Question

The string is formated as '[DATE] record flag: X1.X2.X3.X4.YEAR.NUM;' , where DATA is a date string; there is one or two spaces between : and X1 ; X1 , X2 , X4 are composed of one or more chars ; X3 consisits of zero or more chars ; YEAR and NUM are 4 and 3 digits , respectively.

Here is an exmaple: s = '[2011-03-13] record flag: NW.SENSOR..MH1.2011.012;'

How do I cut 'NW' and 'SENSOR' from s ?

Answer 1

Using str.split :

>>> s = '[2011-03-13] record flag: NW.SENSOR..MH1.2011.012;'

>>> s.split(' ')[3].split('.')
['NW', 'SENSOR', '', 'MH1', '2011', '012;']

>>> out = s.split(' ')[3].split('.')

>>> out[0]
'NW'

>>> out[1]
'SENSOR'

---

Using re.search :

>>> s = '[2011-03-13] record flag: NW.SENSOR..MH1.2011.012;'

>>> out = re.search(r':\s+([^.]+)\.([^.]+)', s)

>>> out.group(1)
'NW'

>>> out.group(2)
'SENSOR'

Answer 2

Use some splitting and stripping:

parts = s.split(":")[1].strip().split(".")
parts[0] # Should be NW
parts[1] # Should be SENSOR