[英]overload delete[] for array of pointers
I search a method to overload operator of delete[] or suitable destructor for a code:我搜索了一种方法来重载 delete[] 运算符或代码的合适析构函数:
#include <iostream>
#include <string>
using namespace std;
class A {
private:
string name;
public:
A(string name){
this->name=name;
};
~A(){
cout<<"Destructor. Destroyed "<<name<<"\n";
};
void operator delete(void* p, A* a){
cout<<"-Delete "<<a->name<<"\n";
};
void operator delete(void* pointer){
cout<<"Delete"<<"\n";
};
void operator delete[](void* pointer){
cout<<"Delete[]"<<"\n";
};
};
int main(){
int number = 5;
A** a = new A* [ number ];
delete [] a;
system("pause");
return 0;
};
But whatever I tried default delete[] is started each time from the file delete2.cpp.但是无论我尝试什么,每次都从文件 delete2.cpp 启动默认的 delete[]。 What do I do wrong?
我做错了什么? [ADDED] Added an attempt to overload delete[].
[添加] 添加了重载 delete[] 的尝试。
Your code is not creating or destroy instances of A, only pointers to it.您的代码不会创建或销毁 A 的实例,只是指向它的指针。
#include <iostream>
#include <string>
using namespace std;
class A {
private:
string name;
public:
A() {}
A(string name){
this->name=name;
};
~A(){
cout<<"Destructor. Destroyed "<<name<<"\n";
};
void operator delete(void* p, A* a){
cout<<"-Delete "<<a->name<<"\n";
};
void operator delete(void* pointer){
cout<<"Delete"<<"\n";
};
void operator delete[](void* pointer){
cout<<"Delete[]"<<"\n";
};
};
int main(){
int number = 5;
A* a = new A[ number ];
delete [] a;
system("pause");
return 0;
};
Calls operator[] as expected: http://ideone.com/EuS3Hi按预期调用 operator[]: http : //ideone.com/EuS3Hi
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