简体   繁体   English

指针数组的重载 delete[]

[英]overload delete[] for array of pointers

I search a method to overload operator of delete[] or suitable destructor for a code:我搜索了一种方法来重载 delete[] 运算符或代码的合适析构函数:

#include <iostream>
#include <string>
using namespace std;

class A {
private:
    string name;
public:
    A(string name){
        this->name=name;
    };
    ~A(){
        cout<<"Destructor. Destroyed "<<name<<"\n";
    };
    void operator delete(void* p, A* a){
        cout<<"-Delete "<<a->name<<"\n";
    };
    void operator delete(void* pointer){
        cout<<"Delete"<<"\n";
    };
    void operator delete[](void* pointer){
        cout<<"Delete[]"<<"\n";
    };
};

int main(){
int number = 5;
A** a = new A* [ number ];

delete [] a;
    system("pause");
    return 0;
};

But whatever I tried default delete[] is started each time from the file delete2.cpp.但是无论我尝试什么,每次都从文件 delete2.cpp 启动默认的 delete[]。 What do I do wrong?我做错了什么? [ADDED] Added an attempt to overload delete[]. [添加] 添加了重载 delete[] 的尝试。

Your code is not creating or destroy instances of A, only pointers to it.您的代码不会创建或销毁 A 的实例,只是指向它的指针。

#include <iostream>
#include <string>
using namespace std;

class A {
private:
    string name;
public:
    A() {}
    A(string name){
        this->name=name;
    };
    ~A(){
        cout<<"Destructor. Destroyed "<<name<<"\n";
    };
    void operator delete(void* p, A* a){
        cout<<"-Delete "<<a->name<<"\n";
    };
    void operator delete(void* pointer){
        cout<<"Delete"<<"\n";
    };
    void operator delete[](void* pointer){
        cout<<"Delete[]"<<"\n";
    };
};

int main(){
int number = 5;
A* a = new A[ number ];

delete [] a;
    system("pause");
    return 0;
};

Calls operator[] as expected: http://ideone.com/EuS3Hi按预期调用 operator[]: http : //ideone.com/EuS3Hi

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM