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如何根据JavaScript中的事件对象获取文件名?

[英]How to get filename based on the event object in JavaScript?

Imagine that an HTML file page1.html has a script tag for base.js . 想象一下,HTML文件page1.html有一个base.js的脚本标记。 In base.js (ie external JavaScript file), I assign onclick listener to a button that exists in page1.html . base.js (即外部JavaScript文件)中,我将onclick监听器分配给page1.html中存在的button Furthermore, base.js is included in script tags across page1.html , page2.html , etc., and each button in each page*?*.html has the same onclick listener assigned to it. 此外, base.js包含在page1.htmlpage2.html等的script标记中,每个page*?*.html每个button page*?*.html都分配了相同的onclick监听器。

Now, I need to somehow know in the base.js which HTML file invoked the onclick listener, in other words, in which page*?*.html webpage the method was fired. 现在,我需要以某种方式在base.js中知道哪个HTML文件调用了onclick监听器,换句话说,在哪个page*?*.html网页中触发了该方法。 Ideally, I would get the filename of that page*?*.html , where ? 理想情况下,我会得到该page*?*.html的文件名page*?*.html ,在哪里 could be 1, 2, 3, etc. Is there a way to accomplish that? 可能是1,2,3等。有没有办法实现这一目标? The code should look like this... 代码看起来应该是这样的......

// fires up when a button in 'page*?*.html' is clicked
function myOnClickEventHandler(e) {
    // the file where myOnClickEventHandler originated from is:
    var filename = e.???????
}

Thank you! 谢谢!

var filename = location.href.match(/([^\\/]*?)$/)[1];

在这个页面上,它是“如何获取基于文件名的事件对象在javascript中”

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