[英]How to convert nested sql into Codeigniter Active record
How do I write query statement in CodeIgniter active record? 如何在CodeIgniter活动记录中编写查询语句?
Here is View code in menu.php file with php procedure. 这是带有php过程的menu.php文件中的View代码。 (this code can run) (此代码可以运行)
<?php
$m=1;
echo "<table>
<tr>
<td>No</td><td>Menu</td><td>Submenu 1</td><td>Submenu 2</td><td>Submenu 3</td>
</tr>";
// main menu
$query1 = $this->db->query("select id,title,parent,order from tbl_menu where parent='0' order by order;");
foreach($query1->result_array() as $r) {
echo "<tr>
<td>$m</td><td>$row[title]</td><td>-</td><td>-</td><td>-</td>
</tr>";
$m++;
$s1=1;
// submenu 1
$query2 = $this->db->query("select * from tbl_menu where parent='$row[id]' order by order;");
foreach($query2->result_array() as $r) {
echo "<tr>
<td></td><td >$s1</td><td>$r[title]</td><td>-</td><td>-</td>
</tr>";
$s1++;
$s2=1;
// submenu 2
$query3 = $this->db->query("select * from tbl_menu where parent='$r[id]' order by order;");
foreach($query3->result_array() as $r2) {
echo "<tr>
<td></td><td></td><td >$s2</td><td>$r2[title]</td><td>-</td>
</tr>";
$s2++;
$s3=1;
// submenu 3
$query4 = $this->db->query("select * from tbl_menu where parent='$r2[id]' order by order;");
foreach($query4->result_array() as $r3) {
echo "<tr>
<td></td><td></td><td></td><td>$s3</td><td>$r3[title]</td>
</tr>";
$s3++;
} // submenu 3
} // submenu 2
} // submenu 1
} // main menu
echo"</table>";
?>
I changed into this... (this is error) 我改成这个...(这是错误的)
<?php
$m=1;
echo "<table>
<tr>
<td>No</td><td>Menu</td><td>Submenu 1</td><td>Submenu 2</td><td>Submenu 3</td>
</tr>";
// main menu
foreach($query1 as $r) {
echo "<tr>
<td>$m</td><td>$row[title]</td><td>-</td><td>-</td><td>-</td>
</tr>";
$m++;
$s1=1;
// submenu 1
foreach($query2 as $r) {
echo "<tr>
<td></td><td >$s1</td><td>$r[title]</td><td>-</td><td>-</td>
</tr>";
$s1++;
$s2=1;
// submenu 2
foreach($query3 as $r2) {
echo "<tr>
<td></td><td></td><td >$s2</td><td>$r2[title]</td><td>-</td>
</tr>";
$s2++;
$s3=1;
// submenu 3
foreach($query4 as $r3) {
echo "<tr>
<td></td><td></td><td></td><td>$s3</td><td>$r3[title]</td>
</tr>";
$s3++;
} // submenu 3
} // submenu 2
} // submenu 1
} // main menu
echo"</table>";
?>
Here is Model code in Menu_model.php file. 这是Menu_model.php文件中的模型代码。
<?php
class Menu_model extends CI_Model {
public function menu_q1() {
$this->db->select('*')->from('tbl_menu')->where('parent','0')->order_by('order', 'ASC');
$query1 = $this->db->get();
return $query1->result_array();
}
public function menu_q2() {
$this->db->select('*')->from('tbl_menu')->where('parent',$row['id'])->order_by('order', 'ASC');
$query2 = $this->db->get();
return $query2->result_array();
}
public function menu_q3() {
$this->db->select('*')->from('tbl_menu')->where('parent',$r['id'])->order_by('order', 'ASC');
$query3 = $this->db->get();
return $query3->result_array();
}
public function menu_q4() {
$this->db->select('*')->from('tbl_menu')->where('parent',$r2['id'])->order_by('order', 'ASC');
$query4 = $this->db->get();
return $query4->result_array();
}
}
?>
Here is Controller code in Menu_controller.php file. 这是Menu_controller.php文件中的控制器代码。
<?php
Class Menu_controller extends CI_Controller {
function __construct(){
parent::__construct();
$this->load->model('menu_model'); //Load profil_model
}
public function profil() {
$query1 = $this->profil_model->menu_q1();
$query2 = $this->profil_model->menu_q2();
$query3 = $this->profil_model->menu_q3();
$query4 = $this->profil_model->menu_q4();
$this->load->view('profil', array('query1' => $query1,'query2' => $query2,'query3' => $query3,'query4' => $query4));
}
?>
This is the table 这是桌子
-------------------------------------------------------- No | Menu | Submenu 1 | Submenu 2 | Submenu 3 -------------------------------------------------------- $m | $row[title] | - | - | - | $s1| $r[title] | - | - | | $s2| $r2[title] | - | | | $s3| $r3[title] --------------------------------------------------------
But getting error in this statement: 但是在此语句中出现错误:
1) where('parent',$row['id']) 1)where('parent',$ row ['id'])
2) where('parent',$r['id']) 2)where('parent',$ r ['id'])
3) where('parent',$r2['id']) 3)where('parent',$ r2 ['id'])
That error is occurring because you are not passing the data into model function. 发生该错误是因为您没有将数据传递给模型函数。 You cannot use any data without pass value to function. 如果没有传递值,则无法使用任何数据。
public function menu_q2($row) {
$this->db->select('*')->from('tbl_menu')->where('parent',$row['id'])->order_by('order', 'ASC');
$query2 = $this->db->get();
return $query2->result_array();
}
public function menu_q3($r) {
$this->db->select('*')->from('tbl_menu')->where('parent',$r['id'])->order_by('order', 'ASC');
$query3 = $this->db->get();
return $query3->result_array();
}
public function menu_q4($r2) {
$this->db->select('*')->from('tbl_menu')->where('parent',$r2['id'])->order_by('order', 'ASC');
$query4 = $this->db->get();
return $query4->result_array();
}
If you pass the value in function (example code above), then you can use that in respectively function. 如果在函数中传递值(上面的示例代码),则可以在函数中分别使用该值。
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