timeIntervalSince1970以毫秒为单位使用什么类型？

Question

I need time since Epoch in ms for an API request, so I'm looking to have a function that converts my myUIDatePicker.date.timeIntervalSince1970 into milliseconds by multiplying by 1000. My question is what should the return value be?

Right now I have

func setTimeSinceEpoch(datePicker: UIDatePicker) -> Int {
    return Int(datePicker.date.timeIntervalSince1970 * 1000)
}

Will this cause any issues? I need an integer, not a floating point, but will I have issues with overflow? I tested it out with print statements and it seems to work but I want to find the best way of doing this.

Answer 1

Looking at Apple Docs :

var NSTimeIntervalSince1970: Double { get }

There is a nice function called distantFuture. Even if you use this date in you func the result will be smaller then the max Int.

let future = NSDate.distantFuture() // "Jan 1, 4001, 12:00 AM"
print((Int(future.timeIntervalSince1970) * 1000) < Int.max) // true

So, until 4001 you're good to go. It will work perfectly on 64-bits systems.

Note: If your system supports iPhone 5 (32-bits) it's going to get an error on pretty much any date you use. Int in Iphone 5 corresponds to Int32. Returning an Int64 is a better approach. See this .